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Lana71 [14]
4 years ago
12

What is the answer to 8=4(v+3)-8v

Mathematics
2 answers:
krok68 [10]4 years ago
4 0
The answer would be 1
vaieri [72.5K]4 years ago
3 0
8 = 4(v + 3) - 8v
8 = 4v + 12 - 8v
8 - 12 = -4v - 8v
-4 = - 12v
-4/-12 = v
1/3 = v <==
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A rabbit is running at a speed of 45 miles per hour. How many feet is the rabbit traveling each second?
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66

Step-by-step explanation:

The rabbit is traveling 66 ft per second.

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Mrs. Kelso and Mr. Bonham gave each their student a small bag of colored tiles. The student each counted the number of purple ti
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The area of a trapezium is 31.5 cm². If the parallel sides are of length 7.5 cm and 5.3 cm, calculate the perpendicular distance
spin [16.1K]

Answer:

<h3>The answer is 4.9cm</h3>

Step-by-step explanation:

To find the perpendicular distance between them that's the height we use the formula

Area \:  \: of \:  \: a \:  \: trapezium =  \frac{1}{2} (a + b) \times h

where

a and b are the parallel sides of the trapezium

h is the perpendicular distance

From the question

Area = 31.5cm²

a = 7.5 cm

b = 5.3 cm

Substituting the values into the above formula we have

31 .5 =  \frac{1}{2} (7.5 + 5.3) \times h

31.5 =  \frac{1}{2}  \times 12.8h

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Divide both sides by 6.4

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We have the final answer

<h3>h = 4.9cm</h3>

Hope this helps you

4 0
3 years ago
Suppose you want to count the number of​ four-letter passwords that can be formed using the letters in the word NUMBER. The four
WITCHER [35]

Answer:

D.The password must not follow order matter

Step-by-step explanation:

We are given that suppose you want to count the number of four letters password that can be formed using the letters in the word NUMBER.

We are given that all letters in the password must be all different .There is no nothing saying about order so we can make combination without order .

We have to find the number of 4- letter password that can be formed using letters in the word NUMBER.

By using Permutation formula we find the number of 4- letters password that can be formed by using the letters N,M,B,U,E,R.

Permutation formula : The number of arrangements when taken r objects at a time out of n objects

=\frac{n!}{(n-r)!}

Total letters in word NUMBER=N,U,M,B,E,R=6

n=6,r=4

Therefore, the number of arrangements  can be made from 6 letters when 4 letters taken at a time =\frac{6!}{(6-4)!}

The number of selection can be made from 6 letters when 4 letters taken at a time =\frac{6!}{(6-4)!}

The number of selection can be made from 6 letters when 4 letters taken at a time =\frac{6\times5\times 4\times3 \times 2!}{ 2!}

n!=n(n-1)(n-2)(n-3)...........3\cdot.2\cdot.1

The number of selection can be made from 6 letters when 4 letters taken at a time =360

Option D is correct.

Answer : D.The password must not follow order matter

6 0
4 years ago
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