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evablogger [386]
2 years ago
6

Solve the problem. If at a given speed a car can travel 95.6 miles on 4 gallons of gasoline, how far can the car can travel on 6

8 gallons of gasoline at that speed? O 95.6 miles 1625.2 miles 68 miles 1632.6 miles
Mathematics
1 answer:
VMariaS [17]2 years ago
3 0

Answer:  The correct option is (B) 1625.2 miles.

Step-by-step explanation:  Given that at a given speed a car can travel 95.6 miles on 4 gallons of gasoline.

We are to find the distance that the car can travel on 68 gallons at the same speed.

We will be using the UNITARY method to solve the given problem.

Distance traveled by the car on 4 gallons of gasoline = 95.6 miles.

So, the distance traveled by the car on 1 gallon of gasoline will be

\dfrac{95.6}{4}=23.9~\textup{miles}.

Therefore, the distance traveled by the car in 68 gallons of gasoline is given by

23.9\times68=1625.2~\textup{miles}.

Thus, the required distance traveled by the car on 68 gallons of gasoline is 1625.2 miles.

Option (B) is CORRECT.

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Marrrta [24]

Answer: (x+10)^2+(y+6)^2=121

Step-by-step explanation:

The equation of a circle in the general form is:

 ax^{2}+by^2+cx+dy+e=0

The equaton of  a circle in standard form is:

(x-h)^2+(y-k)^2=r^2

Where the center is at <em>(h, k)</em> and <em>r</em> is the radius

To write the equation of a circle from general form to standard form, you must complete the squaare, as you can see below:

1- Given the equation in general form:

x^{2}+y^2+20x+12y+15=0

2- Complete the square:

-Group the like terms and move the constant to the other side.

- Complete the square on the left side of the equation.

- Add the same value to the other side.

Then you obtain:

(x^{2}+20x)+(y^2+12y)=-15\\(x^2+20x+(\frac{20}{2})^2)+(y^2+12y+(\frac{12}{2})^2)=-15+(\frac{20}{2})^2+(\frac{12}{2})^2\\\\(x+10)^2+(y+6)^2=-15+100+36\\(x+10)^2+(y+6)^2=121

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3 years ago
Find all unit vectors that are orthogonal to the vector u = 1, 0, −4 .
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Answer:

Step-by-step explanation:

Given:

u = 1, 0, -4

In unit vector notation,

u = i + 0j - 4k

Now, to get all unit vectors that are orthogonal to vector u, remember that two vectors are orthogonal if their dot product is zero.

If v = v₁ i + v₂ j + v₃ k is one of those vectors that are orthogonal to u, then

u. v = 0                    [<em>substitute for the values of u and v</em>]

=> (i + 0j - 4k) . (v₁ i + v₂ j + v₃ k)  = 0               [<em>simplify</em>]

=> v₁ + 0 - 4v₃ = 0

=> v₁ = 4v₃

Plug in the value of v₁ = 4v₃ into vector v as follows

v = 4v₃ i + v₂ j + v₃ k              -------------(i)

Equation (i) is the generalized form of all vectors that will be orthogonal to vector u

Now,

Get the generalized unit vector by dividing the equation (i) by the magnitude of the generalized vector form. i.e

\frac{v}{|v|}

Where;

|v| = \sqrt{(4v_3)^2 + (v_2)^2 + (v_3)^2}

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This is the general form of all unit vectors that are orthogonal to vector u

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