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Alexxandr [17]
3 years ago
12

Explain how the formation of sea ice affects the salinity of ocean water

Biology
1 answer:
dedylja [7]3 years ago
3 0

The answer is; Formation of sea ice increases the salinity of the oceans

When ice form in water, this water is ‘osmotically isolated’ (in solid form) hence making liquid water become lesser in quantity than before. Since the number of dissolved salts remain more or less the same and the liquid water in which it is dissolved has reduced, then the water becomes more concentrated (because they are now more ppm of salts in each cubic amount of the water).


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What is another way genetic variation increase in a population?
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In humans, Rh-positive individuals have the Rh antigen on their red blood cells, while Rh-negative individuals do not. If the Rh
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Answer: 60%

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In population genetics, the Hardy-Weinberg Principle states that the genetic composition of a population remains in equilibrium as long as no natural selection or other factors are active and no mutations occur.

The frequencies of the genotypes of an individual locus will be set to a particular equilibrium value.<u> It also specifies that these equilibrium frequencies can be represented as a simple function of the allelic frequencies at that locus</u>. In the simplest case, with a locus with two alleles A and a, with allele frequencies of p and q respectively, the principle predicts that <u>the genotypic frequency for the dominant homozygous AA is p^2, that of the heterozygous Aa is 2pq and that of the recessive homozygous aa, is q^2. The allele frequency of a is represented as p and the frequency of recessive allele is q.</u>

The three genotypes AA : Aa : aa appear in a ratio p² : 2pq : q². If we add them up, we get the unit:

p^2 + 2pq + q^2 = (p + q)^2 = 1  

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<u>Rh-positive genotypes are represented as AA (homozygous dominant) or Aa (heterozygous) since the presence of a single dominant allele is sufficient to express the phenotype. While Rh-negative genotypes are represented as aa. </u>

If 84% of the population is Rh-positive, that means that this percentage includes all those who are AA and Aa. Then 16% are aa.

F(aa)=q^2=0.16

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So F(Aa)= 2pq = 2 x 0.6 x 0.4 = 0.48

Notice that 0.36 + 0.16 + 0.48 = 1

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What foods should you eat if you want to increase your intake of complex carbohydrates? Simple carbohydrates?
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