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Setler [38]
3 years ago
13

I need you to show me how to solve 228÷6 using base 10 blocks

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
5 0
The answer is 38 to your question
avanturin [10]3 years ago
4 0
Hello! :)
Base ten blocks can't be broken apart, so if you want to solve this question, you can use one blocks. Although it may take a long time to solve larger numbers with blocks, you'll learn long division soon (it's not that hard!) and dividing will become much quicker and less tedious!

If there are 22 base ten blocks and 8 one blocks (228), you'd need to divide them into 6 different groups.

In the end, you should get 38 in each group!
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I'm not really a big fraction type person, but I'm sure it's 7.625
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Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim
Ber [7]

The given function is

f(x)=4\cos \text{(}\pi x)+1

The general form of the cosine function is

y=a\cos (bx+c)+d

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}

The equation of the midline is

y_{ml}=\frac{y_{\max }+y_{\min }}{2}

Since the maximum is at the greatest value of cos, which is 1, then

\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}

Since the minimum is at the smallest value of cos, which is -1, then

\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}

Then substitute them in the equation of the midline

\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0
1 year ago
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\\ \sf\longmapsto

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

4 0
3 years ago
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