Step-by-step explanation:
k(a) =3a+2
k(2)=3*2+2
k(2)=6+2
k(2)=8
Answer is x+9=11
6+x=9
x=3
15=x+12
x=3
7+x=10
x=3
x+9=11
x=2
So x+9=11 has a different x value than the rest of the equations. So it doesn't belong with the other three.
Step-by-step explanation:
Let's get our relevant base equations listed out:
d = 2r
area = pi*r²
c = πd
Thus, d=2*5m = 10m, c=π*10m=10π m, and area = 25m²*π
Feel free to ask further questions!
