We are asked to determine the value of a such that the function f(x) = ax^2 + 5 is fit for the point given (-1,2). In this case, we substitute 2 to y and -1 to x. The result is then 2 = a*(-1)^2 + 5 ; 2 = a + 5; a is then equal to -3
For x,
(32+x)/2=14
32+x=14*2
32+x=28
x=28-32
x=-4
For y,
(40+y)/2=26
40+y=26*2
40+y=52
y=52-40
y=12
Therefore coordinates of B(-4,12)
Hope this helps!
Answer- 4x-6
explain- i got it right
I think your answer is y=-4/7x+5
