Subtract 10 from both sides
10 + x < 5
10 - 10 + x < 5 - 10
x < -5
So the answer is x < -5, or x is less than -5. Any number less than -5 would be the solution. Hope this helps!
For large candles, the price is $10. They sold 42, we can say that. 42*10 is the total price or revenue without the cost to make the candles included. The cost to make the candles is $x. So we can say profit for large candles = (420 - 42x).
For small candles. The price is $5 and 56 are sold. The cost is again $x. So the profit for small candles is (280 - 56x).
So the total profit for part one of your question is (420 - 42x) + (280 - 56x).
In part to we are told that large candles cost $5 and small candles cost $3. Substituing this into are expression gives (420 - 42(5)) + (280 - 56(3)). This gives us $322. So the total profit is $322.
Answer:
D: The function has a hole when x = 3, and vertical asymptotes when x = 0 and x = 5.
Step-by-step explanation:
The given rational function has vertical asymptotes and holes. Remember that an asymptote is placed when the function has undetermined results, when we give a x-value and the y-value cannot be determined, there we say exists an asymptotes, which is a punctual line that represents a discontinuation of the graph, the trace cannot cross that asymptote, it divide the whole function graph.
So, in this case we have to undetermined results when the function has a hole of x = 3, and vertical asymptotes when x = 0 and x = 5.
<u>(2 x y) </u>is a factor of (6 x y), so it's the highest common factor of both expressions.
Given P is T, q is F and r is F.
Let us find p ↔ q first.
↔ is called bi-conditional operator and is true when p and q both are matched.
Since here p is T and q is F, p↔q is F. ( Since p and q are not matching)
~p v r = ~T v F = F v F = F
Hence (p↔q)→(~pvr) = F → F = T (Since conditional operator → is false if and if first proposition is T and second proposition is F, for all other values it is T)
