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Bad White [126]
2 years ago
15

8x − 4y = −16 3x + 15y = −6

Mathematics
1 answer:
mr_godi [17]2 years ago
6 0

Answer:

good job that is correct

Step-by-step explanation:

goooooooooooooooooooooooood joooooooooooooooob

yep

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a trader always 12% discount and sold a fan at a loss of rs 16 if he had sold it at 10% discount he will have gain rupees 20 for
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profit = 30number is the answer of that question answer sapai

3 0
3 years ago
Read 2 more answers
What is the common ratio for the geometric sequence?
sashaice [31]
What is the common ratio for the geometric sequence?

24,−6,3/2,−3/8,...

Common ratio=-1/4

5 0
3 years ago
What is true about the figure below?
VARVARA [1.3K]

Answer:

the answer is b

Step-by-step explanation:

7 0
2 years ago
A pyramid has a base 16 inches x 16 inches and a slant height of 10 inches. what is the volume in cubic inches
gizmo_the_mogwai [7]

Answer:

  512 in³

Step-by-step explanation:

The height perpendicular to the base is the leg of a right triangle with hypotenuse 10 in and other leg 8 in. Using the Pythagorean theorem, we can find it as ...

  h² +8² = 10²

  h² = 100 -64 . . . . . subtract 8²

  h = 6 . . . . . . . . . . . . take the square root of 36

Then the volume is found using ...

  V = (1/3)Bh = (1/3)(16 in)²(6 in) = 512 in³

The volume is 512 cubic inches.

_____

The 8-inch dimension used above comes from half the distance between the center of one side of the base to the center of the opposite side. (16 in)/2 = 8 in.

4 0
3 years ago
Help me to answer this question pl​s
attashe74 [19]

Problem 1

Draw a straight line and plot P anywhere on it. Use the compass to trace out a faint circle of radius 8 cm with center P. This circle crosses the previous line at point Q.

Repeat these steps to set up another circle centered at Q and keep the radius the same. The two circles cross at two locations. Let's mark one of those locations point X. From here, we could connect points X, P, Q to form an equilateral triangle. However, we only want the 60 degree angle from it.

With P as the center, draw another circle with radius 7.5 cm. This circle will cross the ray PX at location R.

Refer to the diagram below.

=====================================================

Problem 2

I'm not sure why your teacher wants you to use a compass and straightedge to construct an 80 degree angle. Such a task is not possible. The proof is lengthy but look up the term "constructible angles" and you'll find that only angles of the form 3n are possible to make with compass/straight edge.

In other words, you can only do multiples of 3. Unfortunately 80 is not a multiple of 3. I used GeoGebra to create the image below, as well as problem 1.

8 0
2 years ago
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