The number of mole of solute particles are present in 1 mL (exact) of aqueous 0.0040 M Ba(OH)₂ is 0.000004 mole
<h3>What is molarity? </h3>
Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
With the above formula, we can determine the number of mole present in the solution. Detail below:
<h3>How to determine the mole of the solute in the solution</h3>
- Volume of solution = 1 mL = 1 / 1000 = 0.001 L
- Molarity of solution = 0.004 M
- Mole of solute =?
Molarity = mole / Volume
Cross multiply
Mole = Molarity × volume
Mole of solute = 0.004 × 0.001
Mole of solute = 0.000004 mole
Thus, the mole of the solute in the solution is 0.000004 mole
Learn more about molarity:
brainly.com/question/9468209
#SPJ1
Multiply then divide 12g by 4cm3 because 4cm3 equals 64cm divide by 12g or multiply which ever is in the options
This implies, for instance, that 1 kilogram of matter is equivalent to an energy E = (1 kg)×(3×108 m/sec)2 = 9×1016 kg m2/sec2. An energy of 1 kg m2/sec2 is known as 1 joule, for short.
Answer: An energy resource is something that can produce heat, power life, move objects, or produce electricity
