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DIA [1.3K]
4 years ago
11

I need help on scienceI have a 89 on my report card for science and I need to get it to a 98

Chemistry
1 answer:
Hunter-Best [27]4 years ago
8 0
Sorry but I only know a few
17- decomposers
18- decomposition
21- 10% is lost so 90%
You might be interested in
Given the values for C (2.5) and O (3.5), calculate the electronegativity difference in a carbon monoxide bond, CO
34kurt

Answer:

ΔEN CO   = 1.0

Explanation:

To calculate the electronegativity difference, we have to substract the element which has the highest EN to the other, that has a low value.

For this case EN from O - EN from C

Electronegativity is a property of the periodic table that increases diagonally, where Fr and Rb are the elements of less EN while F is the most electronegative element, with a value of 4. This is because F is an element with a high ionization energy and a negative electronic affinity.

ΔEN CO  = 3.5 - 2.5 = 1.0

Electronegativity (EN) describes the ability of an atom to compete for

electrons with other atoms to which it is attached.

7 0
4 years ago
Why do plants cells Need chloroplast? put it in your own words
pentagon [3]

Answer:

I hope this helps u out a bit its my own words

Explanation:

Plant cells use chloroplast as kind of an extra mitochondria in a plant cell. They work together, when a chloroplast gets food through photosynthesis the mitochondria breaks down that food and distributes it through the cell.

3 0
4 years ago
Read 2 more answers
The eagle has landed was said when man landed on mars or on the moon
nekit [7.7K]
The moon, man has not been to mars yet
7 0
3 years ago
An acetic acid buffer containing 0.50 M acetic acid (CH3COOH) and 0.50 M sodium acetate (CH3COONa) has a pH of 4.74. What will t
ad-work [718]

Answer:

pH = 4.71

Explanation:

We can find the pH of a buffer (Mixture of weak acid: CH3COOH, and its conjugate base: CH3COONa) using H-H equation:

pH = pKa + log [CH3COONa] / [CH3COOH]

<em>Where pH is the pH of the buffere = 4.74, pKa the pka of the buffer and [] could be taken as the moles of each reactant.</em>

As initially [CH3COONa] = [CH3COOH], [CH3COONa] / [CH3COOH] = 1:

pH = pKa + log 1

4.74 = pKa

To solve this question we need to find the initial moles of each species, The CH3COONa reacts with HCl to produce CH3COOH. That means the moles of CH3COOH after the reaction are: Initial CH3COOH + Moles HCl

Moles CH3COONa: Initial CH3COONa - Moles HCl.

<em>Moles CH3COOH: </em>

0.100L * (0.50mol / L) = 0.050 moles CH3COOH + 0.0020 moles HCl =

0.052 moles CH3COOH

<em>Moles CH3COONa: </em>

0.100L * (0.50mol / L) = 0.050 moles CH3COONa - 0.0020 moles HCl =

0.048 moles CH3COONa

Using H-H equation:

pH = 4.74 + log [0.048 moles] / [0.052 moles]

<h3>pH = 4.71</h3>
5 0
3 years ago
I’ll give 5 stars and Brainliest plus this is 20 points lol
Daniel [21]

Answer:

I think is b

Explanation:

4 0
3 years ago
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