Which pair of objects is experiencing the greatest gravitational force
2 answers:
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Answer :
Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.
Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.
Rules for Oxidation Numbers are :
- The oxidation number of a free element is always zero.
- The oxidation number of a monatomic ion equals the charge of the ion.
- The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.
- The oxidation number of oxygen (O) in compounds is usually -2.
- The oxidation number of a Group 17 element in a binary compound is -1.
- The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
- The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.
Now we have to determine the oxidation state of the elements in the compound.
(a)
Let the oxidation state of 'S' be, 'x'
Hence, the oxidation state of 'S' is, (+6)
(b)
Let the oxidation state of 'Ca' be, 'x'
Hence, the oxidation state of 'Ca' is, (+2)
(c)
Let the oxidation state of 'Br' be, 'x'
Hence, the oxidation state of 'Br' is, (+1)
(d)
Let the oxidation state of 'N' be, 'x'
Hence, the oxidation state of 'N' is, (+5)
(e)
Let the oxidation state of 'Ti' be, 'x'
Hence, the oxidation state of 'Ti' is, (+4)
(f)
Let the oxidation state of 'Na' be, 'x'
Hence, the oxidation state of 'Na' is, (+1)
Answer:
a. Cyclohexanone
Explanation:
The principle of IR technique is based on the <u>vibration of the bonds</u> by using the energy that is in this region of the electromagnetic spectrum. For each bond, there is <em>a specific energy that generates a specific vibration</em>. In this case, you want to study the vibration that is given in the carbonyl group C=O. Which is located around 1700 cm-1.
Now, we must remember that the <u>lower the wavenumber we will have less energy</u>. So, what we should look for in these molecules, is a carbonyl group in which less energy is needed to vibrate since we look for the molecule with a smaller wavenumber.
If we look at the structure of all the molecules we will find that in the last three we have <u>heteroatoms</u> (atoms different to carbon I hydrogen) on the right side of the carbonyl group. These atoms allow the production of <u>resonance structures</u> which makes the molecule more stable. If the molecule is more stable we will need more energy to make it vibrate and therefore greater wavenumbers.
The molecule that fulfills this condition is the <u>cyclohexanone.</u>
See figure 1
I hope it helps!
