Question

What mass of hydrogen is produced when 192 g of magnesium is reacted with hydrochloric acid?​

Answer 1

$\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}$

$\longrightarrow \sf{Mg+2HCI \Longrightarrow MgCl_2+H_2}$

$\longrightarrow \sf{molMg=129gMg \times \dfrac{1molMg}{24.305gMg=} }$

$\small \sf{\longrightarrow molH_2=7.90molMg \times \dfrac{1molH_2}{1molMg}= 7.90molH_2 }$

$\small \sf{\longrightarrow massH_2=7.90H_2 \times \dfrac{2.016g}{1molH_2}= 7.90molH_2= 15.9 \: gH_2}$

$\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}$

$\small\bm{ The \: mass \: of \:H_2 \: produce \: will \: be \: 15.9 }$ $\bm{grams.}$

Answer 2

Answer:

Mg+2HCL-Magnesium Chloride +Hygrogen

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Explanation:

N.O of moles=Mass\Molar Mass

192÷24=8

1:1

8×2=16