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Crazy boy [7]
2 years ago
14

What mass of hydrogen is produced when 192 g of magnesium is reacted with hydrochloric acid?​

Chemistry
2 answers:
Leona [35]2 years ago
5 0

\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}

\longrightarrow \sf{Mg+2HCI \Longrightarrow MgCl_2+H_2}

\longrightarrow \sf{molMg=129gMg \times \dfrac{1molMg}{24.305gMg=} }

\small \sf{\longrightarrow molH_2=7.90molMg \times \dfrac{1molH_2}{1molMg}= 7.90molH_2 }

\small \sf{\longrightarrow massH_2=7.90H_2 \times \dfrac{2.016g}{1molH_2}= 7.90molH_2= 15.9 \: gH_2}

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

\small\bm{ The  \: mass \: of \:H_2 \: produce \: will \: be \: 15.9 } \bm{grams.}

mariarad [96]2 years ago
3 0

Answer:

Mg+2HCL-Magnesium Chloride +Hygrogen

>

Explanation:

N.O of moles=Mass\Molar Mass

192÷24=8

1:1

8×2=16

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Answer:

see explanation below

Explanation:

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According to this reaction, we can see that the mole ratio between the peroxide and the permangante is 5:2. Therefore, if the titration required 21.3 mL to reach the equivalence point, then, the moles would be:

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But like it was stated before, the mole ratio is 5:2 so:

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