Solid to gas stage changes are known as "sublimation." In many cases, solids transform into gases simply after an intermediate liquid state. It is an endothermic procedure (happens with the absorption of heat from the environment).
Some example:
Freeze drying - Water can be sublimated in sustenance items by utilizing a vacuum.
"Dry ice" or, in other words carbon dioxide and as the name proposes it experiences stage change from solid state to liquid state straightforwardly without wetting or going into liquid state.
a) See free-body diagram in attachment
b) The acceleration is 
Explanation:
a)
The free-body diagram of an object is a diagram representing all the forces acting on the object. Each force is represented by a vector of length proportional to the magnitude of the force, pointing in the same direction as the force.
The free-body diagram for this object is shown in the figure in attachment.
There are three forces acting on the object:
- The weight of the object, labelled as
(where m is the mass of the object and g is the acceleration of gravity), acting downward - The applied force,
, acting up along the plane - The force of friction,
, acting down along the plane
b)
In order to find the acceleration of the object, we need to write the equation of the forces acting along the direction parallel to the incline. We have:

where:
is the applied force, pushing forward
is the frictional force, acting backward
is the component of the weight parallel to the incline, acting backward, where
m = 2 kg is the mass of the object
is the acceleration of gravity
is the angle between the horizontal and the incline (it is not given in the problem, so I assumed this value)
a is the acceleration
Solving for a, we find:

Learn more about inclined planes:
brainly.com/question/5884009
#LearnwithBrainly
Answer:
yeah, Do you want me to check your answers? Yes is correct
Answer:
4.8L ( i.e 4.8 x 10^-3 m3)
Explanation:
Step 1:
Data obtained from the question.
Initial volume (V1) = 4.2L
Initial temperature (T1) = 0°C
Final temperature (T2) = 37°C
Final volume (V2) =?
Step 2:
Conversion of celsius temperature to Kelvin temperature. This is illustrated below
K = °C + 273
T1 = 0°C = 0°C + 273 = 273K
T2 = 37°C = 37°C + 273 = 310K
Step 3:
Determination of the final volume.
Since the pressure is constant,
Charles' Law equation will be applied as shown below:
V1 /T1 = V2/T2
4.2/273 = V2 /310
Cross multiply to express in linear form
273 x V2 = 4.2 x 310
Divide both side by 273
V2 = (4.2 x 310)/273
V2 = 4.8L ( i.e 4.8 x 10^-3 m3)
Therefore, the volume of the air in the lungs at that point is 4.8L ( i.e 4.8 x 10^-3 m3)