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o-na [289]
3 years ago
13

When a 109 dB sound wave comes through an open window of area 0.485 m2, how much acoustic energy passes through the window in a

10.9 min interval?
Physics
1 answer:
Ksju [112]3 years ago
7 0

Answer:

57dB

Explanation:

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What are the 3 basic parts of an atom and what are their charges?
kotegsom [21]

Answer:

electrons neutrons and protons

Explanation:

electron are negative

nuetron are neutral

protons are positive

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3 years ago
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7 0
3 years ago
A sliver cylindrical rod has a length of 0.5 m and a radius of 0.4 m, find the density of the rod if it's mass is 2.640 kg
Serga [27]

Answer:

Density=10.50kg/m³

Explanation:

Solution,\\Height(h)=0.5m\\Radius(r)=0.4m\\Now, \\Volume=\pi r^{2} h\\\\Volume=\pi *(0.4m)^{2} *0.5m\\\\Volume=0.251327m^{3} \\\\Again,\\\\Density=\frac{mass}{volume} \\\\Density=\frac{2.640kg}{0.251327} \\\\Density=10.50kg/m^{3}

7 0
2 years ago
In which labeled portion of the curve would you use the heat of vaporization to calculate the heat absorbed? (image attached ins
sergij07 [2.7K]
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3 0
3 years ago
The nucleus of a hydrogen atom is a single proton, which has a radius of about 1.2 × 10-15 m. The single electron in a hydrogen
Nutka1998 [239]

Answer: 0.86 × 10^14

Explanation:

Given the following :

Radius of proton = 1.2 × 10-15 m

Radius of hydrogen atom = 5.3 × 10-11 m

Density of proton could be calculated thus:

Mass of proton = 1.67 × 10^-27 kg

Using the formula :

(4/3) × pi × r^3

(4/3) × 3.142 × (1.2 × 10^-15)^3 = 7.24 × 10^-45

Density = mass / volume

Density = (1.67 × 10^-27) / ( 7.24 × 10^-45)

= 0.2306 × 10^18

Density of hydrogen atom:

Mass of hydrogen atom= 1.67 × 10^-27 kg

Using the formula :

(4/3) × pi × r^3

(4/3) × 3.142 × (5.3 × 10^-11)^3 = 6.24 × 10^-31

Density = mass / volume

Density = (1.67 × 10^-27) / ( 6.24 × 10^-31)

= 0.2676 × 10^4

Ratio is thus:

Density of proton / density of hydrogen atom

0.2306 × 10^18 / 0.2676 × 10^4 = 0.8617 × 10^14

6 0
3 years ago
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