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melomori [17]
4 years ago
5

The equation T^2=A^3 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A

, in astronomical units, AU. If planet Y is twice the mean distance from the sun as planet X, by what factor is the orbital period increased? A. 2^1/3. B. 2^1/2. C. 2^2/3. D. 2^3/2
Physics
1 answer:
kobusy [5.1K]4 years ago
3 0

Answer:

D. 2^(3/2)

Explanation:

Given that

T² = A³

Let the mean distance between the sun and planet Y be x

Therefore,

T(Y)² = x³

T(Y) = x^(3/2)

Let the mean distance between the sun and planet X be x/2

Therefore,

T(Y)² = (x/2)³

T(Y) = (x/2)^(3/2)

The factor of increase from planet X to planet Y is:

T(Y) / T(X) = x^(3/2) / (x/2)^(3/2)

T(Y) / T(X) = (2)^(3/2)

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7 0
3 years ago
What happens when the object is placed at F? Explain your answer.
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Sample Response: No image will be formed because the rays will not converge to or diverge from a common point.

6 0
3 years ago
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Can someone show me the work of this
Alik [6]

Answer:

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Explanation:

7 0
3 years ago
PLEASE HELP!!!!!!
SashulF [63]


Somewhere in your book or your notes, you must have met the formula for the
gravitational attraction between two bodies.  If you can go back and find it, you
only need to plug your numbers into that formula, and out will pop the answer.

Formula:                            <u>Force = G (mA x mB) / (distance)²</u>

If everything is in SI units, then        G = 6.67 x10⁻¹¹ newton-meter² / kilogram²

You said that
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                         mB = 6.5 kg
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   Force = (6.67 x 10⁻¹¹ nt-m²/kg²) (8.1kg x 6.5kg / (0.5m)² =

                (6.67 x 10⁻¹¹ nt-m²/kg²)    ( 52.65 kg² ) / (0.25 m²) =

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7 0
3 years ago
You need to know the height of a tower, but darkness obscures the ceiling. You note that a pendulum extending from the ceiling a
Elis [28]

Answer:

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Thus, tower is 131.3 m tall.

4 0
3 years ago
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