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atroni [7]
3 years ago
9

(x-9)(x+9) find the product

Mathematics
1 answer:
klio [65]3 years ago
7 0

Method 1.

Use (a-b)(a+b)=a^2-b^2

(x-9)(x+9)=x^2-9^2=x^2-81

Method 2.

Use distributive property: (a + b)(c + d) = ac + ad + bc + bd

(x-9)(x+9)=(x)(x)+(x)(9)+(-9)(x)+(-9)(9)=x^2+9x-9x-81=x^2-81

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The equation of a circle is given as:

(x-a)^2 + (y- b)^2 = r^2  where (a, b) is the center.

(x-9)^2  = x^2 -18x + 81 - ----(i)
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Adding equation (i) and (iii) 
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Equating equation (iv) and (iii)

 <span>x^2 + y^2 - 18x + 4y + 85 = 49

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<h2>-  \frac{2}{5}  \div  \frac{3}{4}</h2><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2>-  \frac{2}{5}  \times  \frac{4}{3}</h2><h3>■Multiply the fractions</h3>

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<h3>b) 0.4 \div  ( - 0.75)</h3><h3>■Convert the decimals into a fractions</h3>

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<h2>-  \frac{2}{5}  \div  \frac{3}{4}</h2><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2>-  \frac{2}{5}  \times  \frac{4}{3}</h2><h3>■Multiply the fractions</h3>

<h2>-  \frac{8}{15}</h2><h3>Hence, Quotient is -  \frac{8}{15}</h3>

<h3>c)-  \frac{2}{5}  \div  \frac{3}{4}</h3><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2>-  \frac{2}{5}  \times  \frac{4}{3}</h2><h3>■Multiply the fractions</h3>

<h2>-  \frac{8}{15}</h2><h3>Hence, The Quotient is -  \frac{8}{15}</h3>
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