All categories

3 years ago

Calculate the ratio to the nearest hundredth (Please do them all for me)PLEASE!

Mathematics

1 answer:

earnstyle [38]3 years ago

8 0

All of them are 3.14

I got them all right on I ready :)))

You might be interested in

Find the value of x and y in the diagram below.

defon

Answer:

Step-by-step explanation:

cos 30 = 9/x

x = 9/( $\sqrt{3}/2$ ) = 6 $\sqrt{3}$

(6 $\sqrt{3}$ )² - 9² = x²

x² = 27

x = 3 $\sqrt{3}$

7 0

3 years ago

Help sos help sos help sos

Setler [38]

If multiple Option 1 and 2. If Only 1 option 1

7 0

3 years ago

GCF of 28,42,and 56.<br><br> Please show work

natta225 [31]

<h2>Answer: 14</h2>

Step-by-step explanation:

If we factorize the numbers, we may be able to surmise the GCF:

28 = 2 × 2 × 7

42 = 2 × 3 × 7

56 = 2 × 2 × 2 × 7

∴ the GCF is 2 × 7 = 14

4 0

3 years ago

Find 4 consecutive odd numbers whose sum is 456<br><br><br> plz help me... :')

Effectus [21]

Answer:

4 consecutive odd numbers are 111, 113, 115 and 117.

Step-by-step explanation:

Let the first odd number be x.

So the next odd number will be (x+2)

and the next two consecutive odd numbers are (x+ 4) and (x+6)

According to question,

The sum of all four odd consecutive numbers = 456

⇒ x + (x+ 2) + (x+4) + (x+6) = 456

or, 4x + 12 = 456

⇒ 4x = 456 - 12 = 444

⇒ x = 444/4 = 111

Hence, the first odd number = 111

Second odd number = 111+ 2 = 113

Third odd number is x + 4 = 111 + 4 = 115

And last odd number is x + 6 = 111 + 6 = 117

So, 4 consecutive odd numbers are 111, 113, 115 and 117.

3 0

3 years ago

To send a standard letter through First-Class mail, the cost depends on the weight of the letter. Any letter one ounce or less w

Hitman42 [59]

Answer:

Let x represents the total weight of the parcel and f(x) represents the cost of the parcel,

Then, according to the question,

Any letter one ounce or less will need $0.46 in postage.

That is, For 0 < x ≤ 1, f(x) = 0.46

For each additional ounce over that, or any part of an ounce, the sender must add $0.20 more postage,

Also, the maximum weight = 16 ounces,

0.46 + 0.20 (x-1)= 16

⇒ 0.20 (x-1) = 15.54

⇒ x-1 = 77.7⇒ x = 78.7

Hence, the function that shows the cost of the letter having weight greater than 1 ounces is,

And, for 1 < x ≤ 78.7 f(x) = 0.46 + 0.20(x-1),

Thus, the complete function that shows the given situation is,

$f(x) = \begin{Bmatrix}0.46, & 0\leq x\leq1\\ 0.46+0.20(x-1) & 1$

Thus, we get two line, y = 0.46 and y = 0.46 + 0.20(x-1),

Which are plotted in the below graph.

3 0

3 years ago