One custodian cleans a suite of offices in 3 hours. When a second worker is asked to join the regular custodian, the job takes o nly 2 hours. How long does it take the second worker to do the same job alone?
1 answer:
Answer:
6 hours
Step-by-step explanation:
Let x represent the time in hours it takes the second worker to do the job alone. Then each hour, 1/x of the job gets done by that worker. Similarly, the regular custodian accomplishes 1/3 of the job in each hour. Working together, they do 1/2 of the job each hour:
1/3 +1/x = 1/2
1/x = 1/2 -1/3 = 3/6 -2/6 = 1/6 . . . . subtract 1/3 and simplify
x = 6
It takes the second worker 6 hours to do the same job alone .
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Answer:
4
Step-by-step explanation:
Answer:
Hourly
Step-by-step explanation:
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Tan=24/10 ≈ 2.4
using Pythagoras theorem
x²=(24)²+(10)²
x²=576+100
x²=57600
x=√57600 => 240
Therefore
sina=24/240 => 0.1
cota=1/tana => 1/(24/10) => 10/24
The answer is 13 because you would plug in 3(3) which is 9 then you multiply (9)(2) which is 18 they you subtract 18-5 which equals 13