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slega [8]
3 years ago
12

You rotate triangle ABC, with vertices A(-3, 1), B(-2, 2), and C(-3, 4), 90° counterclockwise about the origin to form triangle

A′B′C′. Match each vertex of triangle A′B′C′ to its coordinates. Tiles (2, 2) (-1, -3) (1, 3) (4, 3) (-2, -2) (-4, -3)
Mathematics
2 answers:
katrin2010 [14]3 years ago
6 0
The rule for going 90 degree counter clockwise is:
(x, y) becomes (y, -x)

Therefore, the new points are:

A(-3, 1) to (1, 3)
B(-2, 2) to (2, 2)
C(-3, 4) to (4, 3) 
IRINA_888 [86]3 years ago
6 0

Answer:

The coordinates of <em>A' are (-1,-3) , B' are (-2,-2) , C' are (-4,-3).</em>

Step-by-step explanation:

You rotate triangle ABC, with vertices A(-3, 1), B(-2, 2), and C(-3, 4), 90° counterclockwise about the origin to form triangle A′B′C′.

<em>" When point M (h, k) is rotated about the origin O through 90° in anticlockwise direction. The new position of point M (h, k) will become M'(-k, h) ".</em>

As the coordinates of A are (-3,1)

⇒ h=-3 and k=1

Hence, the coordinates of A' will be (-1,-3)

similarly the coordinates of B are (-2,2)

⇒ h=2 and k=-2

Hence, coordinates of B' are: (-2,-2)

similarly the coordinates of C are (-3,4).

⇒ h=-3 and k=4

Hence, coordinates of C' are (-4,-3).


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Please help me thanks please <br> Will give you brainlest
Akimi4 [234]

Answer:

224

Step-by-step explanation:

<u>Base:</u>

A = Bh

A = 8(8) = 64

<u>Sides:</u>

A = 1/2 Bh

A = 1/2 8(10)

A = 40

<u>Then you do 40(4) because there are 4 sides:</u>

40 (4) = 160

<u>Then you add up the base and the sides:</u>

160 + 64 = 224

(I think this is the right answer)

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Community college students conduct a survey at their college. They ask "Do you plan to transfer to a university to pursue a bacc
Tamiku [17]

Answer:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

For this case the conditions we have the conditions to assume a normal distribution for the population proportion since:

np=100*0.8=80 >10 , n(1-p) = 10*(1-0.8) =20 >10

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The estimated proportion is given by \hat p =\frac{80}{100} =0.8. If we replace the values obtained we got:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

6 0
3 years ago
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