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bogdanovich [222]
3 years ago
11

Suppose a new liquid were discovered that is identical to water in every way except that it has a lower latent heat of fusion. W

ould it take a longer or shorter time to make ice out of this liquid in your freezer? Why?
Chemistry
2 answers:
Sati [7]3 years ago
6 0

Answer:

Shorter

It would take shorter to freeze the new liquid

Explanation:

Let the latent heat of fusion of the new liquid be Y and

Let the latent heat of fusion of water be Z

Where Z = 2×Y for example

Therefore, the heat lost to make ice from a given mass  of water is given by;

Heat loss = Mass of water, m × ΔH(latent) Water

= m × Z

The heat lost to make ice from equal mass of the new liquid is

= m × Y  = m × Z/2 = 0.5× m×Z

Therefore the heat required to be removed to make an equal mass of ice of the new liquid is half that of the heat removed to make an equal mass of ice.

Where the rate of heat extraction is A watts of A J/s we have;

Time required to freeze new liquid = 0.5 × time required to freeze water.

Hence it would take shorter to freeze the new liquid.

faltersainse [42]3 years ago
3 0

Answer:

It would take less time, because having a lower temperature of latent heat means that at a lower temperature it merges, therefore the closer it will be to the temperature of solification which is 0 degrees Celsius or Celsius ... It is then that it would solidify in less time than water

Explanation:

By acting and having all the same properties as water except for latent heat, it considers that the solidification temperature is 0 degrees Celsius like water.

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I need chemistry help! How would I set up these problems?
Bond [772]

Answer: -

1) 8.33 minutes

2) 118.39 in/ s

180.43 m/min

10.83 km/ hr

Explanation: -

Speed of light = 3 x 10⁸ m/s

Distance of the earth from the sun= 93 million miles

We know 1 million = 1,000,000

Also 1 mile = 1609 m

Distance of the earth from the sun= 93 million miles

= 93,000,000 miles.

= 1.5 x 10^{11} m

Time taken = \frac{Distance}{Speed}

= \frac{1.5 x [tex] 10^{11} m}{3 x 10⁸ m/s} [/tex]

= 500 s

= 500/ 60

= 8.33 minutes

2) Distance = 1 mile = 63360 inches

Time taken = 8.92 min

= 8.92 x 60

= 535.2 s

Speed = \frac{distance}{time}

= \frac{63360 inches}{535.2 s}

= 118.39 in/ s

Distance = 1 mile = 63360 inches = 63360 x 2.54 cm = 63360 x 2.54 x 10^{-2} m

Time taken = 8.92 min

Speed = \frac{distance}{time}

= \frac{63360 x 2.54 x [tex] 10^{-2} m}{8.92 min} [/tex]

= 180.43 m/ min

1 m = 10⁻³ Km

1 min = 1/60 hour

1 m /min = 10⁻³ km/ \frac{1}{60 hour}

= 60/1000

=0.06 km/hr

180.43 m / min = 180 x 0.06 km / hr

= 10.93 km / hr

4 0
3 years ago
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