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arlik [135]
3 years ago
8

Ed records the temperature of two pots of water. Pot X has a temperature of 56 degrees Fahrenheit, and pot Y has a temperature o

f 49 degrees Fahrenheit. What conclusion can Ed make about the pots of water? The water in pot X has more kinetic energy than the water in pot Y. The water in pot Y has more kinetic energy that the water in pot X. The water in pot X has a higher specific heat than the water in pot Y. The water in pot Y has a higher specific heat than the water in pot X.
Chemistry
2 answers:
baherus [9]3 years ago
8 0

Answer:

A) The water in pot X has more kinetic energy than the water in pot Y.

7nadin3 [17]3 years ago
6 0

Answer:

Itś A) The water in pot X has more kinetic energy than the water in pot Y.

Explanation:

Did it on a quiz

ed2020

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Be sure to answer all parts. In the average adult male, the residual volume (RV) of the lungs, the volume of air remaining after
Alenkinab [10]

<u>Answer:</u>

<u>For a:</u> The number of moles of air present in the RV is 0.047 moles

<u>For b:</u> The number of molecules of gas is 2.83\times 10^{22}

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the number of moles, we use the equation given by ideal gas follows:

PV=nRT

where,

P = pressure of the air = 1.00 atm

V = Volume of the air = 1200 mL = 1.2 L    (Conversion factor:  1 L = 1000 mL)

T = Temperature of the air = 37^oC=[37+273]K=310K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of air = ?

Putting values in above equation, we get:

1.00atm\times 1.2L=n_{air}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 310K\\n_{air}=\frac{1.00\times 1.2}{0.0821\times 310}=0.047mol

Hence, the number of moles of air present in the RV is 0.047 moles

  • <u>For b:</u>

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules.

So, 0.047 moles of air will contain (0.047\times 6.022\times 10^{23})=2.83\times 10^{22} number of gas molecules.

Hence, the number of molecules of gas is 2.83\times 10^{22}

7 0
3 years ago
How many moles of sodium ions are present in 0.25 kg of a 2.0 m solution of sodium chloride in water
LenKa [72]

0.50 is the answer on edge

8 0
3 years ago
If HCl is a 0.05 M solution and 50 mL is used to titrate the NaOH, what is the molarity of NaOH if the flask contains 100 mL?
Liono4ka [1.6K]

Answer:

Molarity of NaOH = 0.025 M

Explanation:

Given data:

Molarity of  HCl = C₁ = 0.05 M

Volume of HCl = V₁= 50 mL

Molarity of NaOH = C₂=?

Volume of NaOH =V₂= 100 mL

Solution:

Formula:

C₁V₁  = C₂V₂

C₁ = Molarity of  HCl

V₁  = Volume of HCl

C₂ = Molarity of NaOH

V₂ = Volume of NaOH

Now we will put the values:

C₁V₁  = C₂V₂

0.05 M × 50 mL = C₂ × 100 mL

2.5 M.mL =C₂ × 100 mL

C₂  = 2.5 M.mL /100 mL

C₂  = 0.025 M

7 0
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How are the molecules moving in a cold glass of water compared to in a warm glass of water
taurus [48]
Molecules move faster in a warm glass of water they move slower in a cold glass of water
4 0
3 years ago
The removal of one or more electrons from a neutral atom results in and
Studentka2010 [4]

Answer:

The removal of one or more electrons from a neutral atom results in a cation.

Explanation:

When you remove electrons from a neutral atom, the atom becomes more positive. Electrons have a negative charge and the protons inside of the nucleus have a positive charge. When electrons are removed, the positive charges from the protons outweigh the negative charges. This results in a positively charged atom, called a cation.

6 0
1 year ago
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