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3 years ago

At what temperature does water evaporate?

Chemistry

2 answers:

Ymorist [56]3 years ago

7 0

100 Celsius that is your answer

Alexus [3.1K]3 years ago

4 0

It evaporates at 100°

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At exactly 2:00 PM, speedy the hermit crab crawl onto a meter stick starting at the 10 cm mark. If he reaches the 60 cm mark at

kvv77 [185]

Answer:

speed=5cm/minute

Explanation:

Given at 2:00PM the hermit is at 10cm mark

Also given that the hermit reaches 60cm mark at 2:10PM

Therefore the time elapsed is 10 minutes = $10\times 60=600 seconds$

the distance travelled by the hermit is 60-10=50cm=0.5m

We know that

$speed=\frac{distane}{time}$

$speed=\frac{0.5}{600}$

speed = $8.3\times 10^{-4}$ m/sec=5cm/minute

3 0

3 years ago

Calculate the molarity of a solution prepared by dissolving 5.850g of solid NaCl in enough water to make 200mL of the solution?

Y_Kistochka [10]

See the attachment below. Thanks :)

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3 years ago

23. The reaction

Sindrei [870]

Answer:

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3 years ago

A solution of hydrochloric acid of unknown concentration was titrated with 0.10 M NaOH. If a 100.-mL sample of the HCl solution

madam [21]

<u>Answer:</u> The initial pH of the HCl solution is 3

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?M\\V_1=100mL\\n_2=1\\M_2=0.10M\\V_2=1mL$

Putting values in above equation, we get:

$1\times M_1\times 100=1\times 0.10\times 1\\\\M_1=\frac{1\times 0.10\times 1}{1\times 100}=10M$

1 mole of HCl produces 1 mole of $H^+$ ions and 1 mole of $Cl^-$ ions

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

$[H^+]=0.001M$

Putting values in above equation, we get:

$pH=-\log (0.001)\\\\pH=3$

Hence, the initial pH of the HCl solution is 3

6 0

3 years ago

How many liters is 1.9 mol of Cl2 at STP?

Lena [83]

Answer:

V = 42.6 L

Explanation:

Given data:

Number of moles of Cl₂ = 1.9 mol

Temperature and pressure = standard

Volume occupy = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

By putting values,

1 atm × V = 1.9 mol ×0.0821 atm.L /mol.K × 273.15 k

V = 42.6 atm.L / 1 atm

V = 42.6 L

8 0

2 years ago