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shepuryov [24]
2 years ago
7

Which one of the following compounds will be least soluble in water?

Chemistry
2 answers:
algol [13]2 years ago
8 0

Water is a polar solvent. Since, 'Like dissolves like' a polar compound will be most soluble in water whereas a non-polar compound will be the least soluble.

The increasing order of polarity for the given organic compounds is:-

CH3OCH3 < CH3NH2 < CH3CHO < CH3CH2OH

Ether is the least polar and hence least soluble in water.

Juliette [100K]2 years ago
7 0

Answer: The correct answer is (A).

Explanation :

CH_3OCH_3 that is dimethyl ether will be least soluble in water because extent of hydrogen bonding interaction with water molecules are weakest in comparison to other listed options.

Where as :

  • In CH_3CH_2OH that is ethanol,in which extent of inter-molecular hydrogen bonding with water molecules will be highest due to the presence of polar (-OH) group.Where as (-NH_2) group is less polar than that of the (-OH) group.
  • in CH_3NH_2 that is methyl amine in which extent of hydrogen bonding will higher than than that of the CH_3CHO that is ethanal. This is due to presence of two hydrogen atoms in primary amine which are available for inter-molecular hydrogen bonding with water molecules.

So, the order  of solubility from least soluble to highly soluble compound in water will be:

CH_3OCH_3

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Step 2 : Set up ICE table

We will set up an ICE table for the above reaction

Following points are considered while drawing ICE table

- The initial concentration of product is assumed as 0

- The change in concentration (C) is assumed as x. Change (x) is negative for reactants and positive for products

- The coefficients in balanced equation are considered while writing C values

Check attached file for ICE table

Step 3 : Set up equilibrium constant equation

The equation for equilibrium constant can be written as

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81.9 = \frac{(2x)^{2}}{(0.437-x) (0.269-x)}

81.9 = \frac{(2x)^{2}}{x^{2} -0.706x + 0.118}

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The concentration of ICl when the reaction reaches equilibrium is 0.508 M

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