Which one of the following compounds will be least soluble in water?
2 answers:
Answer: The correct answer is (A).
Explanation :
that is dimethyl ether will be least soluble in water because extent of hydrogen bonding interaction with water molecules are weakest in comparison to other listed options.
Where as :
- In
that is ethanol,in which extent of inter-molecular hydrogen bonding with water molecules will be highest due to the presence of polar (-OH) group.Where as (
) group is less polar than that of the (-OH) group.
- in
that is methyl amine in which extent of hydrogen bonding will higher than than that of the
that is ethanal. This is due to presence of two hydrogen atoms in primary amine which are available for inter-molecular hydrogen bonding with water molecules.
So, the order of solubility from least soluble to highly soluble compound in water will be:
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Hello!
The pressure of the Ideal Gas when the volume is 1,45 L and the temperature is 298 K is 1,82 atm.
To solve this problem we need to apply the Ideal Gas Law for the initial conditions and the final ones, clearing the equation for the number of moles (n) and the ideal gas constant (R) which remain constant:
Now we match n*R for the initial conditions (1) and the final ones (2), clearing the equation for P₂
Have a nice day!
The pressure of the Ideal Gas when the volume is 1,45 L and the temperature is 298 K is 1,82 atm.
To solve this problem we need to apply the Ideal Gas Law for the initial conditions and the final ones, clearing the equation for the number of moles (n) and the ideal gas constant (R) which remain constant:
Now we match n*R for the initial conditions (1) and the final ones (2), clearing the equation for P₂
Have a nice day!