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3 years ago

An unknown monatomic gas diffuses twice as fast as Br2. What is the identity of this unknown gas?

Chemistry

1 answer:

kirza4 [7]3 years ago

3 0

Answer : The unknown monoatomic gas is, argon.

Explanation :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

$R\propto \sqrt{\frac{1}{M}}$

or,

$(\frac{R_2}{R_1})=\sqrt{\frac{M_1}{M_2}}$ ..........(1)

where,

$R_1$ = rate of effusion of unknown gas = 2R

$R_2$ = rate of effusion of $Br_2$ gas = R

$M_1$ = molar mass of unknown gas = ?

$M_2$ = molar mass of $Br_2$ gas = 160 g/mole

Now put all the given values in the above formula 1, we get:

$(\frac{R}{2R})=\sqrt{\frac{M_1}{160g/mole}}$

$M_1=40g/mol$

From the molar mass 40 g/mol we conclude that the unknown monoatomic gas will be, argon.

Therefore, the unknown monoatomic gas is, argon.

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3 years ago

33. Why does Fluorine exert a stronger pull than Chlorine on the valence electrons of another

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3 years ago

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