Which combination best represent the mass and charge of a neutron?

Help PLEASEEE !!!!!! will give brainliest !

BabaBlast [244]

Answer:

6. O₂ + Cu —> CuO

7. H₂ + Fe₂O₃ —> H₂O + Fe

8. O₂ + H₂ — > H₂O

9. H₂S + NaOH —> Na₂S + H₂O

10. Al + HCl —> H₂ + AlCl₃

Explanation:

6. Oxygen gas react with solid copper metal to form copper(II) oxide

Oxygen gas => O₂

Copper => Cu

copper(II) oxide => CuO

The equation is:

O₂ + Cu —> CuO

7. hydrogen gas and iron(III) oxide powder react to form liquid water and solid iron power

hydrogen gas => H₂

Iron(III) oxide => Fe₂O₃

Water => H₂O

Iron => Fe

The equation is:

H₂ + Fe₂O₃ —> H₂O + Fe

8. Oxygen gas react with hydrogen gas to form liquid water

Oxygen gas => O₂

hydrogen gas => H₂

Water => H₂O

The equation is:

O₂ + H₂ — > H₂O

9. Hydrogen sulphide gas is bubbled through a sodium hydroxide solution to produce sodium sulphide and liquid water

hydrogen sulphide => H₂S

sodium hydroxide => NaOH

Sodium sulphide => Na₂S

Water => H₂O

The equation is:

H₂S + NaOH —> Na₂S + H₂O

10. Hydrogen gas and aluminum chloride solutions are produced when solid aluminum react with hydrochloric acid

Aluminum => Al

Hydrochloric acid => HCl

hydrogen gas => H₂

Aluminum chloride => AlCl₃

The equation is:

Al + HCl —> H₂ + AlCl₃

5 0

3 years ago

Describe the flow of blood to the human body, including through each of the four chambers of the heart. Explain how the blood ch

xeze [42]

Hey there,

The blood needs to flow at a great and constant speed. It can not flow very slow because that can be warning's of a heart attack because your blood is using alot of force and its trying to provide as much blood as possible to arrive at the heart in order for your body to live. This is why we should drink water because as we drink water, it helps our blood flow through out our body well and so that we ma not have any problem now and in the future.

~Jurgen

3 0

3 years ago

Read 2 more answers

ASAP, NO TROLLS 20 points!!!!

MA_775_DIABLO [31]

Answer:

1.- Chemical change

2.- Because the atoms in the image are tranformed into a new molecule

3.- Yes, it does

4.- Due to the amount of atoms are the same both in products and reagents

Explanation:

6 0

2 years ago

Read 2 more answers

A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of

Stella [2.4K]

Answer:

See explanation.

Explanation:

Hello,

In this case, we can show how the empirical formula is found by following the shown below procedure:

1. Compute the moles of carbon in carbon dioxide as the only source of carbon at the products:

$n_C=0.01962molCO_2*\frac{1molC}{1molCO_2} =0.01962molC$

2. Compute the moles of hydrogen in water as the only source of hydrogen at the products:

$n_H=0.01961molH_2O*\frac{2molH}{1molH_2O}=0.03922molH$

3. Compute the mass of oxygen by subtracting the mass of both carbon and hydrogen from the 0.4647-g sample:

$m_O=0.4647g-0.01962molC*\frac{12gC}{1molC}-0.03922molH*\frac{1gH}{1molH} =0.1900gO$

4. Compute the moles of oxygen by using its molar mass:

$n_O=0.1900gO*\frac{1molO}{16gO}=0.01188molO$

5. Divide the moles of carbon, hydrogen and oxygen by the moles of oxygen (smallest one) to find the subscripts in the empirical formula:

$C=\frac{0.01962}{0.01188}=1.65\\ \\H=\frac{0.03922}{0.01188} =3.3\\\\O=\frac{0.01188}{0.01188} =1$

6. Search for the closest whole number (in this case multiply by 2):

$C_3H_6O_2$

Moreover, the empirical formula suggests this compound could be carboxylic acid since it has two oxygen atoms, nevertheless, this is not true since the molar mass is 222.27 g/mol, therefore, we should compute the molar mass of the empirical formula, that is:

$M=12*3+1*6+16*2=74g/mol$

Which is about three times in the molecular formula, for that reason, the actual formula is:

$C_9H_{18}O_6$

It suggest that the compound has a highly oxidizing character due to the presence of oxygen, therefore, we cannot predict the distribution of the functional groups as it could contain, carboxyl, carbonyl, hydroxyl or even peroxi.

Best regards.

6 0

3 years ago

Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:

Setler [38]

The order of frequency is d < a < c < b

$E_{n} = 13.6 * z^{2} / n^{2}$ eV

where z = atomic mass number

n = energy level

For hydrogen z = 1

Therefore, Energy for n = 1

$E_{n} = 13.6 * 1^{2} / 1^{2}$ eV

= -13.6 eV

for n = 2

$E_{n} = 13.6 * 1^{2} / 2^{2}$ eV

= -3.40 eV

for n = 3

$E_{n} = 13.6 * 1^{2} / 3^{2}$ eV

= -1.51 eV

for n = 4

$E_{n} = 13.6 * 1^{2} / 4^{2}$ eV

= -0.85 eV

for n = 5

$E_{n} = 13.6 * 1^{2} / 5^{2}$ eV

= -0.544 eV

n = 2 to n = 4 (absorption)

ΔE = E4 - E2 = -0.85 - (-3.40) = 2.55 eV

n = 2 to n = 1 (emission)

ΔE = E1 - E2 = -13.6 - (-3.40) = -10.2eV

The negative sign indicates that emission will take place.

n = 2 to n = 5 (absorption)

ΔE = E5 - E2 = -0.544 - (-3.40) = 2.856 eV

n = 4 to n = 3 (emission)

ΔE = E3 - E4 = -1.51 - (-0.85) = -0.66 eV

We know that

E = h * υ

Therefore, Energy is proportional to frequency.

So increasing the order of energy is

E4 < E1 < E3 < E2

order of frequency is

d < a < c < b

For more information click on the link below:

brainly.com/question/17058029

# SPJ4

8 0

1 year ago