So there are a totally of 52 cards right?(not counting jokers because jokers are not in official cards)
And there are 4 aces right?
So there are 52 outcomes and 4 of them are aces.
So when we write probabilities we write it in fraction form where the total number of outcomes is the denominator and the ones you want to get are the numerator OK?
So the total number is outcomes is 52 and becomes the denominator and 4 the number of aces become the numerator.
So 4/52 right?
And we now have to simplify it right?
And so we divide by the highest common factor right?
In this case 4 because there isn’t other numbers that are factors and greater than 4.
So 4 divided by 4/52 is 1/13 right?
4 goes into 4 1 time and 13 times into 52.
So your answer is 1/13
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It is easy the left side as to be ten times greater then your
right side for example my ones place is ten times greater my tens place
is ten times greater than my hundreds place and my hundreds place is ten
times greater than my thousands place i hope this will help you bye
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Answer:
ok
Step-by-step explanation:
The probability that he will be rejected to at least one of the colleges is 0.51.
Given probability that he will admit in A is 0.7, probability that he will not be admit in B is 0.5, probability that atleast one of his applications got rejected is 0.6.
We have to find the probability that he will be rejected to at least one of the colleges.
Probability that he will admit in A =0.7
Probability that he will not admit in A=1-0.7=0.3
Probability that he will not admit in B =0.5
Probability that he will admit in B=1-0.5=0.5
Probability that he will be rejected to at least one of the colleges=probability that he will admit in A* probability that he will not admit in B+ probability that he will admit in B* probability that he will not admit in A+ probability that he will not admit in A* probability that he will not admit in B
=0.7*0.5+0.5*0.3+0.5*0.3
=0.35+0.15+0.15
=0.51
Hence the probability that he will be rejected to at least one of the colleges is 0.51.
Learn more about probability at brainly.com/question/24756209
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Answer:
yes
Step-by-step explanation:
