Convert 2.91 g to kg

Which of the following is the equation of a line perpendicular to the line, , passing through the point (3,9)?

julsineya [31]

Y = -3/2x + 4...slope is -3/2
A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So that means the slope we will need is 2/3...see how I flipped the slope and changed the sign.
Now we use y = mx + b....slope(m) = 2/3....(3,9)...x = 3 and y = 9.
Time to sub...we r looking for b, the y intercept.

9 = 2/3(3) + b
9 = 2 + b
9 - 2 = b
7 = b

so the perpendicular equation is : y = 2/3x + 7...but we need it in Ax + By = C form....
y = 2/3x + 7....multiply by common denominator of 3 to get rid of fractions
3y = 2x + 21...subtract 2x from both sides
-2x + 3y = 21....<== ur answer...normally, I would have multiplied this by -1 to make x positive...but that is not an answer choice

5 0

3 years ago

I’ll love u forever if u help me with this ASAP PLZZZ I don’t get it plzzz

laiz [17]

Answer:

v= 13

w= -32

Step-by-step explanation:

2v+6w=-36

5v+2w=1

2w= 1-5v

2v+ (3)(1-5v)= -36

2v+3-15v= -36

3-13v =-36

3--36= 13v

39= 13v

13 = V

5×13+2w=1

65+2w=1

1-65= 2w

-64=2w

-32=w

3 0

3 years ago

Please help!!!

Leto [7]

Answer:

- The scientist can use these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.

- The scientist can substitute these measurements into $cos\alpha=\frac{adjacent}{hypotenuse}$ and solve for the distance between the Sun and the shooting star (which would be the hypotenuse of the righ triangle).

Step-by-step explanation:

You can observe in the figure attached that "AC" is the distance between the Sun and the shooting star.

Knowing the distance between the Earth and the Sun "y" and the angle x°, the scientist can use only these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.

This is:

$cos\alpha=\frac{adjacent}{hypotenuse}$

In this case:

$\alpha=x\°\\\\adjacent=BC=y\\\\hypotenuse=AC$

Therefore, the scientist can substitute these measurements into $cos\alpha=\frac{adjacent}{hypotenuse}$ , and solve for the distance between the Sun and the shooting star "AC":

$cos(x\°)=\frac{y}{AC}$

$AC=\frac{y}{cos(x\°)}$

3 0

3 years ago

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What values of a and b make the equation true? sqrt(648)=sqrt(2^a•3^b)

Anuta_ua [19.1K]

ANSWER

The value of a and b are:

$a=3,b=4$

EXPLANATION

The expression given to us is

$\sqrt{648} = \sqrt{ {2}^{a} \times {3}^{b} }$

We square both sides of the equation to obtain

$648= {2}^{a} \times {3}^{b}$

We now find the prime factorization of 648 to obtain,

${2}^{3} \times {3}^{4} = {2}^{a} \times {3}^{b}$

We now compare the exponents on both sides of the equation to obtain,

$a=3,b=4$

Therefore the correct option is C

3 0

3 years ago

Write the number in order to least to greatest 0.15, -4/5, -1.25, 1.03, 2 5/6 and 7/20

svetoff [14.1K]

-1.25,-4/5,7/20,1.03,2 5/6

6 0

3 years ago

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Convert 2.91 g to kg​

Convert 2.91 g to kg