Which of the following is the correct unit for work?

Mazie stands on her kitchen floor. The coefficient of kinetic friction between her socks and the floor is 0.35, and the coeffici

Natasha2012 [34]

Static friction is a force that keeps an object at rest. Static friction definition can be written as: The friction experienced when individuals try to move a stationary object on a surface, without actually triggering any relative motion between the body and the surface on which it is on

<h3>How can calculate the Fs by finding your normal force and multiplying it by your static friction force?</h3>

N = mg = (9.8)×(58) = 568.4N

Fs = NKs = (568.4)×(0.42) =238.7N

b) So this is an interesting question, she's going at a speed of 0.6 m/s. Kinetic friction is pushing her back so theres a negative force which is the force of kinetic friction right. So its NKf = (238.7)×(0.35) = 83.5N

To learn more about Static friction, refer

brainly.com/question/13680415

#SPJ9

4 0

2 years ago

Cells are visualized using light microscopes and electron microscopes. Which statement about microscopes is false. Group of answ

denpristay [2]

Answer:

Light microscopes use light and glass objectives to illuminate and magnify objects

Explanation:

Light microscopes and electron microscopes are used to study cells. The electron microscope has many times more resolving power than the ordinary light microscope. A light microscope contains an objective lens and an eyepiece through which the final image is seen.

Both light and electron microscopes magnifies the image of the object. The magnifying power of an electron microscope is many times that of the light microscope.

4 0

3 years ago

A satellite of mass 5600 kg orbits the Earth and has a period of 6200 s.

Troyanec [42]

Answer:

(a) Radius of orbit will be $=7.32\times10^6m$

(b) Earth gravitational force will be $=4.18\times 10^4N$

(C) Height will be $0.92\times 10^6m$

Explanation:

We have given

Mass of the earth, $M=6\times 10^{24}kg$

Mass of the satellite, m = 5600 kg

Radius of earth, $R=6.4\times 10^6m$

Time period T = 6200 sec

We know that $\omega =\frac{2\pi }{T}=\frac{2\times 3.14}{6200}=0.00101rad/sec$

Now

(a) We know that $\omega ^2=\frac{GM}{R^3}$

$R^3=\frac{GM}{\omega ^2}$

$R^3=\frac{6.67\times 10^{-11}\times 6\times 10^{24}}{0.00101 ^2}$

$R^3=3.92\times 10^{20}$

Radius of the orbit $R=7.32\times 10^6m$

(b)

Force $F=\frac{GMm}{R^2}=\frac{6.67\times 10^{-11}\times 6\times 10^{24}\times 5600}{(7.32\times 10^6)^2}=4.18\times 10^4N$

(c)

Altitude $h=radius\ of\ orbit-radius\ of\ earth=7.32\times 10^6-6.4\times 10^6=0.92\times 10^6m$

8 0

3 years ago

A child of mass M is swinging on a swing set. The ropes attaching the swing to the top bar have length L. Find the gravitational

myrzilka [38]

Answer:

(a) 0

(b) 10ML

(c) $10ML(1 - cos(\theta))$

(d) $10ML(1 + sin(\phi))$

Explanation:

(a) When hanging straight down. The child is at the lowest position. His potential energy with respect to this point would also be 0.

(b) Since the rope has length L m. When the rope is horizontal, he is at L (m) high with respect to the lowest swinging position. His potential energy with respect to this point should be

$E_h = mgh = 10ML$

where g = 10m/s2 is the gravitational acceleration.

(c) At angle $\theta$ from the vertical. Vertically speaking, the child should be at a distance of $Lcos(\theta)$ to the swinging point, and a vertical distance of $L - Lcos(\theta)$ to the lowest position. His potential energy to this point would be:

$E_{\theta} = mgh = 10M(L - Lcos(\theta)) = 10ML(1 - cos(\theta))$

(d) at angle $\phi$ from the horizontal. Suppose he is higher than the horizontal line. This would mean he's at a vertical distance of $Lsin(\phi)$ from the swinging point and higher than it. Therefore his vertical distance to the lowest point is $L + Lsin(\phi) = L(1 + sin(\phi))$

His potential energy to his point would be:

$E_{\phi} = mgh = 10ML(1 + sin(\phi))$

5 0

4 years ago

A ball of 0.5kg slows down from 5m/s to 3m/s. Calculate the work done in the process

ivann1987 [24]

Answer: Cannot determine cause we need to know the change of time to calculate the work.

Explanation:

m = 0.5kg

V = 3m/s - 5m/s = -2m/s

P = W/t = Fv

F = ma

W = Fvt

W = (0.5)(9.8)t = 4.9t

4 0

2 years ago