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Nutka1998 [239]
2 years ago
6

calculate how much charge passes through the LED in 1 hour if the current flowing in the circuit below is 350mA

Physics
1 answer:
Morgarella [4.7K]2 years ago
3 0

Given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.

<h3>What is Current?</h3>

Current is simply the rate of flow of charged particles i.e electrons caused by EMF or voltage.

If a charge passes through the cross-section of a conductor in a given time, the current I is expressed as;

I = Q/t

Where Q is the charge and t is time elapsed.

Given the data in the question;

  • Time elapsed t = 1hr = 3600s
  • Current I = 350mA = 0.35A
  • Charge Q = ?

We substitute our given values into the expression above to determine the charge.

I = Q/t

Q = I × t

Q = 0.35A × 3600s

Q = 1260C

Therefore,  given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.

Learn more about current here: brainly.com/question/3192435

#SPJ1

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Answer:

64 J

Explanation:

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Now W = ∫F.dx

So, ∆U = - ∫F.dx = - ∫Fdxcos180 (since the spring force and extension are in opposite directions)

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=  ∫F.dx

Since F = 40x - 6x² and x moves from x = 0 to x = 2 m, we integrate thus, ∆U =  ∫₀²F.dx

=  ∫₀²(40x - 6x²).dx

=  ∫₀²(40xdx - 6x²dx)

=  ∫₀²(40x²/2 - 6x³/3)

=  ∫₀²(20x² - 2x³)

= [20x² - 2x³]₀²

= [(20(2)² - 2(2)³) - (20(0)² - 2(0)³)

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3 years ago
A bat can detect small objects, such as an insect, whose size is approximately equal to one wavelength of the sound the bat make
blsea [12.9K]

Answer:

6.136 mm

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given,

frequency emitted by the bat = 5.59 x 10⁴ Hz

speed of sound = 343 m/s

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\lambda = 6.136\times 10^{-3}}

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so, the smallest size of insect that bat can hear is equal to 6.136 mm

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