Answer:
The curve length (<em>L</em>) will be = 1218 ft
The elevations and stations for PVC and PVI
a. station of PVC = 103 + 91.00
b. station of PVI = 116 + 09.00
c. elevation of PVC = 432.18ft
d. elevation of PVI = 426.09ft
Explanation:
First calculate for the length (<em>L</em>)
To calculate the length, use the formula of "elevation at any point".
where, elevation at any point = 424.5.
and ∴ PVC Elevation = (420 + 0.01L)
Then, calculate for Station of PVC and PVI and elevation of PVC and PVI
Answer:
Electrons are the negatively charged particles of atom. Electrons are extremely small compared to all of the other parts of the atom. So, the negative green particles of this atom are the electrons.
Explanation:
Hope it helps:)
Answer:
[012] :
Here x component is zero. That is why this is in y- z plane
[721] :
This is in all three plane .It means it is in space.
[110] :
Here z component is zero.
That is why this is in x -y plane
From the cubic unit directions we can easily understand all given directions [012], [721], [110].
Fine grained of alkali igneous rocks cannot be used in cement because of the volume expansion caused by the Alkali-silica reaction, fine-grained igneous rocks cannot be used as aggregates in cement.
<h3>What does fine grained mean in an igneous rock?</h3>
Extrusive igneous rocks have a fine-grained or aphanitic texture, with grains that are too small to see without a magnifying glass. The fine-grained texture suggests that the rapidly cooling lava did not have enough time to form large crystals. A petrographic microscope can be used to examine these tiny crystals.
The texture of an igneous rock (fine-grained vs coarse-grained) is determined by the rate at which the melt cools: slow cooling produces large crystals, while fast cooling produces small crystals.
The chemical reaction that occurs in both alkali cations and hydroxyl ions in the pore solution of hydrated cement paste and certain reactive silica phases present in concrete aggregates is known as the alkali-silica reaction (ASR).
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Answer:
μ = 0.55
Explanation:
Given that
Normal weight = 1.8 x weight of person
N= 1.8 mg
We know that friction force Fr
Fr= μ N
μ=Coefficient of friction
N=Normal force
To find μ We have to equate friction and gravity force
Fr= Wt
μ N = m g
μ x 1.8 m g = m g
μ = 0.55
So the coefficient of friction will be 0.55.
