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tamaranim1 [39]
2 years ago
14

What’s the answer to this I don’t understand

Engineering
1 answer:
kari74 [83]2 years ago
3 0

Answer:

Electrons are the negatively charged particles of atom. Electrons are extremely small compared to all of the other parts of the atom. So, the negative green particles of this atom are the electrons.

Explanation:

Hope it helps:)

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the truck shown weighs 16 tonnes when empty. the truck has a capacity of 36m3 volume for the crude oil. calculate the total weig
SVETLANKA909090 [29]

Answer:

573 is correct answer

Explanation:

ok bro

5 0
3 years ago
dentify a semiconducting material and provide the value of its band gap) that could be used in: (a) (1 point) red LED (b) (1 poi
OLga [1]

Answer:

(a) Aluminum Indium Gallium Phosphide (AlInGaP). Band gap = 1.81eV  ≈ 2eV

(b) Gallium Nitride (GaN). Band Gap = 3.4eV

(c) Aluminium Gallium Arsenide (AlGaA). Band Gap = 1.42eV ≈ 2.16eV

(d) Zinc Selenide (ZnSe). Band Gap = 2.82eV

(e) Gallium Phosphide (GaP). Band Gap = 2.24eV

Explanation:

LED's are semi-conducting materials that convert electrical energy to light energy. The light color emitted from the LED depends on the semi-conducting material and other compositions.

The band gap of the semi-conductor determines its wavelength. High band gap semi-conductors emit lower wavelengths which means greater power(UV semi-conducting macterials fall under this category).

5 0
3 years ago
The energy flux associated with solar radiation incident on the outer surface of the earth’s atmosphere has been accurately meas
Degger [83]

Answer:

A) 3.868x10^26 W

B) 8176.678 K

C) 3.544x10^-7 m

D) 393.187 K

Explanation:

Detailed explanation and calculation is shown in the image below.

8 0
3 years ago
Three single-phase, 10 kVA, 460/120 V, 60 Hz transformers are connected to form a three-phase 460/208 V transformer bank. The eq
evablogger [386]

Answer:

A) attached below

B) I₁ = 18.1 A ,  I₂ = 69.39 A

C)  V( magnitude) = 454.5 ∠ 5.04° V ,  Voltage regulation = ≈  -1.2%

Explanation:

A) Schematic diagram attached below

attached below

<u>B) magnitude of primary and secondary winding currents </u>

I₂ ( secondary current ) = P / √3 * VL * cos∅ ---------- ( 1 )

VL = Line voltage = 208

cos∅  ( power factor ) = 0.8

P = 20 * 10^3 watts

insert values into equation 1

I₂ = 69.39 A

I₁ ( primary current ) = I₂V2 / V1

                               I₁ = ( 69.39 * 120 ) / 460  = 18.1 A

<u>C ) Calculate the Primary voltage magnitude and the Voltage regulation</u>

V(magnitude ) = Vp + ( I₁ ∠∅ ) Req                            ( 1 + j2 = 2.24 ∠63.43° )

                       = 460 + ( 18.1 * cos^-1 (0.8) ) ( 1 + j2 )

                       = 460 + 40.544 ∠ 100.3°

∴ V( magnitude) = 454.5 ∠ 5.04° V

<em>Voltage regulation </em>

= ((Vmag - V1) / V1 )) * 100

= (( 454.5 - 460 / 460 )) * 100

= -1.195 % ≈  -1.2%

8 0
3 years ago
What best describes the relationship between missionaries and Native Americans?
Vlad [161]

Answer:

Missionaries taught the Native Americans to read but allowed them to keep their customs. Native Americans and missionaries fought in battles

Explanation:

sorry if this doesn't help u but i hope it does!

6 0
3 years ago
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