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enyata [817]
1 year ago
14

If weather conditions are such that it is required to designate an alternate airport on your IFR flight plan, you should plan to

carry enough fuel to arrive at the first airport of intended landing, fly from that airport to the alternate airport, and fly thereafter for45 minutes at normal cruising speed
Engineering
1 answer:
yulyashka [42]1 year ago
4 0

It is TRUE to state that if weather conditions are such that it is required to designate an alternate airport on your IFR flight plan, you should plan to carry enough fuel to arrive at the first airport of intended landing, fly from that airport to the alternate airport, and fly thereafter for 45 minutes at normal cruising speed.

<h3>What is IFR Flight Plan?</h3>

IFR flight planning is an acronym for Instrument Flight Rules, a phrase used to describe flight planning when the pilot expects to utilize onboard instruments for navigation.

IFR is used when the conditions in an aircraft are deemed too dangerous to rely solely on visual cues.

Learn more about IFR Flight Plan:
brainly.com/question/28089224
#SPJ1

Full Question:

If weather conditions are such that it is required to designate an alternate airport on your IFR flight plan, you should plan to carry enough fuel to arrive at the first airport of intended landing, fly from that airport to the alternate airport, and fly thereafter for45 minutes at normal cruising speed

True or False

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7 0
3 years ago
The magic square is an arrangement of numbers in a square grid in such a way that the sum of the numbers in each row, and in eac
Yuki888 [10]

Answer:

See the explanation for the answer;

Explanation:

Matlab code is as given below

-------------------------------------------------------------------------------------Start of code

% Program to create a magic square and verify it

clc

M= magic(5)

% To find sum of elements of each row

r1= sum(M(1,:))      % Sum of row 1

r2= sum(M(2,:))      % Sum of row 2

r3= sum(M(3,:))      % Sum of row 3

r4= sum(M(4,:))      % Sum of row 4

r5= sum(M(5,:))      % Sum of row 5

% To find sum of each coloumn

c1= sum(M(:,1))      % Sum of coloumn 1

c2= sum(M(:,2))      % Sum of coloumn 2

c2= sum(M(:,3))      % Sum of coloumn 3

c2= sum(M(:,4))      % Sum of coloumn 4

c2= sum(M(:,5))      % Sum of coloumn 5

% To find sum of diagonal

d1= sum(diag(M))               % Sum of principal diagonal elements

d2= sum(diag(fliplr(M)))      

-------------------------------------------------------------------------------End of code

Following results are obtained when executed.

M =

   17    24     1     8    15

   23     5     7    14    16

    4     6    13    20    22

   10    12    19    21     3

   11    18    25     2     9

r1 =

   65

r2 =

   65

r3 =

   65

r4 =

   65

r5 =

   65

c1 =

   65

c2 =

   65

c2 =

   65

c2 =

   65

c2 =

   65

d1 =

   65

d2 =

   65

3 0
3 years ago
The inverted U-tube is used to measure the pressure difference between two points A and B in an inclined pipeline through which
JulijaS [17]

Answer:

i) 0.610 m or 610 mm

ii) 0.4 m or 400 mm

Explanation:

The pressure difference between the pipes is

a) Air

Pa + πha +Ha = Pb + πhb +Hb

Pa - Pb = π(hb-ha) + Hb-Ha

Relative density of air = 1.2754 kg /m3

Pa - Pb = 1.2754 * 0.4 + (0.3-0.2) = 0.610 m or 610 mm

b) paraffin of relative density of 0.75

Pa - Pb = π(hb-ha) + Hb-Ha

Pa - Pb = 0.75 * 0.4 + (0.3-0.2) = 0.4 m or 400 mm

8 0
3 years ago
Who is the inventor that created the light bulb
vlada-n [284]

Answer:

Thomas Elva Edison

He invented light.

3 0
3 years ago
A hollow, spherical shell with mass 2.00kg rolls without slipping down a slope angled at 38.0?.
mezya [45]

Answer:

\mu = 0.31

Explanation:

Given data:

mass = 2.00 kg

slope angle = 38.0

From figure

balancing force

mgsin\theta - f = ma   .....1

Balancing torque

F_R = \frac{2}{3} mR^2 \alpha ......2

for pure rolling

\alpha  = \frac{a}{R}

F = \frac{2}{3} ma

from 1 and 2nd equation

mgsin\theta - \frac{2}{3}ma =  ma

mgsin\theta = \frac{5}{3} ma

a = \frac{3}{5} g sin\theta

 = \frac{3\theta 9.8 sin 38}{5} = 3.62 m/s^2

F =\mu N

   = \frac{2}{3} ma

   = \frac{2}{3} 2\times 3.62 = 4.83 N

N =normal force =  mgsin\theta = 2 \times 9.8 sin 38 = 15.44 N

\mu \times 15.44 = 4.83

solving for  coefficent of friction we get

\mu = 0.31

4 0
3 years ago
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