Answer:
22 people would be expected to participate in the survey.
Step-by-step explanation:
We are given that a research company found that 11% of the people that they called agreed to participate in a survey.
The company called 196 people and we have to find that how many would be expected to participate in the survey.
The above situation can be represented through binomial distribution;
![P(X=r)=\binom{n}{r} \times p^{r}\times (1-p)^{n-r}; x = 0,1,2,3,.....](https://tex.z-dn.net/?f=P%28X%3Dr%29%3D%5Cbinom%7Bn%7D%7Br%7D%20%5Ctimes%20p%5E%7Br%7D%5Ctimes%20%281-p%29%5E%7Bn-r%7D%3B%20x%20%3D%200%2C1%2C2%2C3%2C.....)
where, n = number of trials (samples) taken = 196 people
r = number of success
p = probability of success which in our question is probability
that people agreed to participate in a survey, i.e; p = 11%
Let X = <em><u>Number of people who agreed to participate in a survey</u></em>
SO, X ~ Binom(n = 196, p = 0.11)
Now, the expected number of people who would participate in the survey is given by;
E(X) =
=
= 21.56 ≈ <u>22 people</u>
<u></u>
Hence, 22 people would be expected to participate in the survey.