Answer:
.
![Ran \{g(x)\} = (m\cdot j+p,m\cdot k +p)](https://tex.z-dn.net/?f=Ran%20%5C%7Bg%28x%29%5C%7D%20%3D%20%28m%5Ccdot%20j%2Bp%2Cm%5Ccdot%20k%20%2Bp%29)
Step-by-step explanation:
From Mathematics we remember that the domain of a functions corresponds to the set of values of the independent variable (
in this case) so that images exist and the range of a function is the set of images.
In this case, we know the domain and range of
and we must find the domain and range of
.
Domain
The domain of
is the domain of
. That is,
.
Range
We have to define the bounds of the range of
, given that range
is modified by streching and horizontal translation operations:
Lower bound (
)
![g(x) = m\cdot j +p](https://tex.z-dn.net/?f=g%28x%29%20%3D%20m%5Ccdot%20j%20%2Bp)
Upper bound (
)
![g(x) = m\cdot k +p](https://tex.z-dn.net/?f=g%28x%29%20%3D%20m%5Ccdot%20k%20%2Bp)
In consequence, the range of
is ![Ran \{g(x)\} = (m\cdot j+p,m\cdot k +p)](https://tex.z-dn.net/?f=Ran%20%5C%7Bg%28x%29%5C%7D%20%3D%20%28m%5Ccdot%20j%2Bp%2Cm%5Ccdot%20k%20%2Bp%29)
Answer:
1001
1
Step-by-step explanation:
If a quadratic function crosses the x-axis twice, it has two solutions. For a quadratic function in
with discriminant
, the following is true:
- If
, then the quadratic has two real solutions - If
, then the quadratic has one real solution - If
, then the quadratic has no real solutions
Therefore, in order to have two solutions, a quadratic's discriminant must be larger than 0. The only two answer choices that satisfy this are 1001 and 1.
Answer:
7- (y/4)
Step-by-step explanation:
Answer:
ac+ad+bc+bd
Step-by-step explanation:
PLS mark me brainiest