Since segments ST and PQ are parallel, triangles SRT and PRQ are similar due to the AAA postulate. In general, the ratio between the corresponding sides of two similar triangles is constant; therefore,
Furthermore,
Finding PR and RS,
Then,
Solving for PS,
Solve the quadratic equation in terms of PS, as shown below
![\begin{gathered} \Rightarrow PS^2+16PS-132=0 \\ \Rightarrow PS=\frac{-16\pm\sqrt[]{16^2-4(-132)}}{2}=\frac{-16\pm28}{2} \\ \Rightarrow PS=-22,6 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5CRightarrow%20PS%5E2%2B16PS-132%3D0%20%5C%5C%20%5CRightarrow%20PS%3D%5Cfrac%7B-16%5Cpm%5Csqrt%5B%5D%7B16%5E2-4%28-132%29%7D%7D%7B2%7D%3D%5Cfrac%7B-16%5Cpm28%7D%7B2%7D%20%5C%5C%20%5CRightarrow%20PS%3D-22%2C6%20%5Cend%7Bgathered%7D)
And PS is a segment; therefore, it has to be positive.
Hence, the answer is PS=6
X > -10 + 5
bring the five to the other side of the equation and change the sign in front
x > -5
20 cm^2. Type in 20.
2*4 makes 8 divided by two makes 4. There are four sides so do 4*4 to make 16. 2*2 for the middle to make 4. 16+4 makes 20 cm^2
Answer:
Step-by-step explanation:
If I remember expanded form is putting all number in terms of being times 10 to a power. starting with the ones place it's x10^0 which of course is just 1, so you don't need to include the x10 at all.
now, moving one either way that 0 either get 1 added to it or subtracted. So in the 10s place it becomes x10^1 and the tenths place becomes x10^-1. Similarly the hundreds place and hundreths place will have x10^2 and x10^-2 respectively. So keep this pattern going to find each place of the number. Can you list out what places are displayed in 5.625?
I will get you started, but let me know if you don't quite get it.
5 + 6*10^-1 + ...
Can you figure out the rest?
