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MAVERICK [17]
3 years ago
10

Graph: y-3= 1/2(x+2)

Mathematics
1 answer:
Readme [11.4K]3 years ago
6 0

Answer: (-8,0) (0,4)

Step-by-step explanation: graphing it would be for coordinate one (-8,0) and for the second coordinate it would be (0,4.) and for the x y chart it goes for x's it goes -8 and then next is 0 and for the y's, it's 0 then next is 4. give me brainliest thankssss

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Elaine found the following in her pocket. How much money was in her pocket
jenyasd209 [6]

Answer:

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3 0
2 years ago
A triangle has sides with lengths of 2x - 7, 5x - 3, and 2x - 2. What is the perimeter
alex41 [277]
P=2x-7 + 5x-3 +2x-2
P= 9x -12
6 0
3 years ago
Can someone please help me with math
allsm [11]

Answer:

the answer is D

Step-by-step explanation:

the graph has a negative correlation

5 0
3 years ago
What is the area of this triangle ?
oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}

We need to find the lengths of side DE, EF and FD

Length of side DE = a = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side DE = a = =\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60

Length of side EF = b = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side EF = b = =\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8

Length of side FD = c = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side FD = c = =\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle==\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88

So, area of triangle is 9.88 units^2

4 0
4 years ago
What is 6 over 9 simplified
Snezhnost [94]

Answer:

2/3

Step-by-step explanation:

\frac{6}{9}

\frac{6}{9}  =  \frac{2 \times 3}{3 \times 3}

=  \frac{2}{3}  \times  \frac{3}{3}

=  \frac{2}{3}  \times 1 =  \frac{2}{3}

I hope it helped you

3 0
2 years ago
Read 2 more answers
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