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3 years ago

Which of the following is a sign that a person may be attempting to meet an unrealistic health goal?

2 answers:

7 0

The correct answer should be a tendon rupture

Weight loss, muscle strength, and increased joint flexibility are quite common for people who work out regularly. Tendons rupture however occurs when people do something that they were not designed to do.

Sloan [31]3 years ago

3 0

Answer:

The correct answer is option - tendon rupture.

Explanation:

The unrealistic health goal is a goal or aim that required more skills, talent or the ability than actually available to achieve it by an individual. Unrealistic goals normally result in side effects or negative effects on the body.

Tendon rupture is one of the signs of the person attempt unrealistic health goals as tendon separates because of intense exercise and diet plans that are not reasonable.

Thus, the correct answer is - tendon rupture.

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714,000 = mass water x specific heat water x 30.
Substitute specific heat water and solve for mass water.

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If the mass of the book is 50 sliding with acceleration 1.2 m/s ^ 2 then the friction force is

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3 years ago

Read 2 more answers

In tae-kwon-do, a hand is slammed down onto a target at a speed of 14 m/s and comes to a stop during the 3.0 ms collision. Assum

GrogVix [38]

Answer:

A) The impulse is 11,7 kg.m/s . B) The average force on the hand is 3900N

Explanation:

Givens:

Hand's mass (m)= 0,90kg

Hand's initial velocity (vi)= 14m/s

Time of collision (t)= 3ms

A) Impulse is the change of momentum of an object when the object is acted upon by a force for an interval of time. We use the formula:

/F/ = m. /Δv/

Where:

F= Force of Impulse

m= Mass

Δv= change in speed ( vf-vi)

Using that formula we get:

/F/= 0,90kg . / (0m/s-14m/s) /

/F/=0,90kg . 14m/s

/F/ = 11,7 kg. m/s

*note that (vf) is 0 because the hand stops in the action, so it's final

velocity = 0

B)The average force is equal to the change in the momentum over the change in time. We use the formula:

/F/= m. (Δv) : Δt

Where:

F= the average force from the target

m= the mass of the hand

Δv= hange in speed (vf/vi)

Δt= change in time

*if we look closely, we find the we alredy have half of the equation because we have alredy calculated m.(Δv) in point A.

We boil the equation down to:

/F/= Impulse : Δt

/F/= 11,7kg.m/s : 0,003s

/F/= 3900N

*we use 0,003s as our time because the given time was 3ms.

*the final result is expressed in Newtons because our final result ends up beeing kg.m/s² = N

8 0

4 years ago

1. A 455 g mass, hanging at rest on a spring, stretches the spring 22.4 cm beyond its relaxed

pishuonlain [190]

Answer:

19.9 N/m

Explanation:

From the question,

Applying Hook's law

F = Ke.................. Equation 1

Where F = Force on the spring, k = spring constant, e = extension

But the force on the spring is the weight of the mass

Therefore,

mg = ke.................. Equation 2

Where m = mass. g = acceleration due to gravity

make e the subject of the equation

e = mg/e................ Equation 3

Given: m = 455 g = 0.455 kg, e = 22.4 cm = 0.224 m,

Constant: g = 9.8 m/s²

Substitute these values into equation 3

e = (0.455×9.8)/0.224

e = 19.9 N/m

6 0

3 years ago