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Lapatulllka [165]
4 years ago
11

I need help with these questions

Physics
1 answer:
stira [4]4 years ago
5 0

Answer:

was there a reading that your class did on this

Explanation:

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Complete the statement by filling in the Blanks:
Anika [276]

Answer:

induced current

Explanation:

intentionally manipulated.

5 0
3 years ago
If you push a chair across the floor at a cibstant velocity how does the force of friction compare with the force you exert?
Roman55 [17]

-- "constant velocity"   ===>    acceleration is 0 .

-- acceleration=0   ===>   forces are balanced

-- balanced forces   ===>  (friction) + (force you exert)  =  0

                                           (friction) = -(force you exert)

                        They have equal magnitude and opposite direction. 

7 0
4 years ago
A 3.50-meter length of wire with a cross-sectional area of 3.14 × 10-6 meter2 is at 20° Celsius. If the wire has a resistance of
maks197457 [2]

Answer:

5.6\times 10^{-8}\ Ohm.m

Explanation:

Resistivity is given by \rho=\frac {AR}{L} where A is cross-sectional area, R is resistance, L is the length and \rho is the reistivity. Substituting 0.0625 for R, 3.14 × 10-6 for A and 3.5 m for L then the resistivity is equivalent to

\rho=\frac {3.14\times 10^{-6}\times 0.0625}{3.5}=5.60714285714285714285714285714285714285\times 10^{-8}\approx 5.6\times 10^{-8}\ Ohm.m

8 0
3 years ago
Two parallel-plate capacitors, identical except that one has twice the plate separation of the other, are charged by the same vo
erik [133]

Answer:

The capacitor having less distance of separation has a stronger electric field.

Explanation:

The capacitors are identical and only difference between them is that one has twice the plate separation of the other. Therefore, capacitance of the given capacitors C1 and C2 is,

C1= Aε/d  and C2=Aε/2d

The charges Q1 and Q2 on the capacitors of capacitance C1 and C2 respectively, is then given by the equation,

Q1=VC1

Q1=VAε/d

Q2=VC2

Q2=VAε/2d

Therefore, the surface charge density σ1 and σ2 for the capacitors is,

σ1=Q1/A

σ1=VAε/(d*A)

σ1=Vε/d

Similarly,

σ2=Q2/A

σ2=Vε/2d

The electric field between the plates is directly proportional to the surface charge density. And so electric field is inversely proportional to the distance of separation. Therefore the capacitor whose distance of separation is less has a stronger electric field.

Check out similar questions.

brainly.com/question/14744776

#SPJ10

8 0
3 years ago
A motivated mule can accelerate an empty cart of mass m - 180 kg from rest to 5.0 m/s in 10 s.
kolezko [41]

When the mass of the cart changes, the time to travel at 4.6 m/s is 28.11 s.

<h3>Acceleration of the mule</h3>

The acceleration of mule is calculated as follows;

a = v/t

a = 5/10

a = 0.5 m/s²

<h3>For constant applied force</h3>

F1 = F2

m₁v₁/t₁ = m₂v₂/t₂

(180 x 5) / 10 = (550 x 4.6)/t

90 = 2530/t

t = 2530/90

t = 28.11 s

Thus, when the mass of the cart changes, the time to travel at 4.6 m/s is 28.11 s.

Learn more about acceleration here: brainly.com/question/14344386

5 0
2 years ago
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