Question

Two fair tetrahedrons (4 sided), each with equal sides numbered from 1 to 4, are identical except that one is red and the other white. If the two tetrahedrons are tossed and the number on the bottom face of each is observed, what is the probability of the the event "the sum of the numbers is 8"

Answer 1

Answer:

Probability of getting an eight is Pr( getting an 8 sum) = 0.0625

Step-by-step explanation;

+ 1 2 3 4

1 2 3 4 5

2 3 4 5 6

3 4 5 6 7

4 5 6 7 8

given below is a table that gives all the possible sums from throwing 2 fair die. it simply is an addition table

from the table we have 16 possible sums and only one is 8. that means that theres only one chance of getting an 8 summation out of 16 throws.

hence probability of getting an eight is Pr( getting an 8 sum) = 1/16 = 0.0625