Let

. Then

. By convention, every non-zero integer

divides 0, so

.
Suppose this relation holds for

, i.e.

. We then hope to show it must also hold for

.
You have

We assumed that

, and it's clear that

because

is a multiple of 3. This means the remainder upon divides

must be 0, and therefore the relation holds for

. This proves the statement.
8+(-10) is like 10-8 except backwards so how i do some problems is like that and then add a negative sign; so say if i were doing 8+(-10), i would do 10-8 which equals 2 and then since 10 is bigger than 8 and it’s a negative number, i would put -2 as my answer
The direction you are traveling to get back home is North
Ans : A and F
Step-by-step explanation: