Force
or motion im not toatally sure
A marble rolls off a tabletop 1.15 m high and hits the floor at a point 4 m away from the edge of the table in the horizontal direction,
- t= 0.45 seconds.
- V=2.22m/s
- VT=4.95 m/s
This is further explained below.
<h3>What is its speed when it hits the floor...?</h3>
Generally, the equation for motion is mathematically given as
S= ut + 0.5at²
Therefore
y = Voy t + 0.5gt^2
1 = 0.5x 98 x 6²
1=4.9t^2

t= 0.45 seconds.
b) Horizontal motions are uniform.
V=Horizontal displacement/time
V=1/0.45
V=2.22m/s
C)
Vx: 2.22 m/s At bottom,
Vy² = Voy² + 2as
Vy² = 2x95x1
Vy² = 19.6
Total velocity

VT=4.95 m/s
Read more about Arithmetic
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Answer:
The energy of each photon in the light beam is
.
Explanation:
Given that,
Index of refraction of glass =1.55
Index of refraction of material =1.30
Wavelength = 115 nm
We need to calculate the energy of each photon in the light beam
Using formula of energy

Where, h = Planck constant
=wavelength
c = speed of light
Put the value into formula


Hence, The energy of each photon in the light beam is
.
Explanation:
Impulse = change in momentum
FΔt = Δp
(53 N) (15 s) = Δp
Δp = 795 kg m/s
For constant mass:
Δp = m Δv
795 kg m/s = (12 kg) Δv
Δv = 66.25 m/s
Rounding to two significant figures, Δp = 800 kg m/s and Δv = 66 m/s.
Answer:
V = 8.34m/s
Explanation:
Given that
1/2ke^2 = 1/2mv^2 ......1
Where e = 3.75cm = (3.75/100)m
e = 0.0375m
K = 500 N/m
m = 10g = 10/1000
= 0.01kg
Substitute the values into equation 1
0.5×500×(0.0375)^2 = 0.5×0.01×v^2
250×0.001395 = 0.005v^2
0.348 = 0.005v^2
v^2 = 0.348/0.005
v^2 = 69.6
V = √69.6
V = 8.34m/s
The ball launches at the speed of V = 8.34m/s