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kvasek [131]
3 years ago
6

A toy rocket is launched from a 1.41.4 m high platform in such a way that its​ height, h​ (in meters), after t seconds is given

by the equation h equals negative 4.9 t squared plus 9.1 t plus 1.4h=−4.9t2+9.1t+1.4. how long will it take for the rocket to hit the​ ground?
Physics
1 answer:
Elena L [17]3 years ago
7 0
In this problem, we are already given the equation for height h in terms of time t. So, the only thing you would do is substitute h and solve for t. If the height is given as 1.414 m, then the solution would be:

h=−4.9t² <span>+ 9.1t +1.4
1.414 = </span>−4.9t² + 9.1t +1.4
−4.9t² + 9.1t - 0.014 = 0

Since this is a quadratic equation, there can be two answer for this equation. They are t = 1.859 seconds, -0.001537 seconds. Since the negative answer is impossible, the answer would be 1.859 seconds.
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