Answer:
After 4 s of passing through the intersection, the train travels with 57.6 m/s
Solution:
As per the question:
Suppose the distance to the south of the crossing watching the east bound train be x = 70 m
Also, the east bound travels as a function of time and can be given as:
y(t) = 60t
Now,
To calculate the speed, z(t) of the train as it passes through the intersection:
Since, the road cross at right angles, thus by Pythagoras theorem:
Now, differentiate the above eqn w.r.t 't':
For t = 4 s:
Answer:
0.0002
Explanation:
First you have to solve exponents first, so you solve 10 to the power of negative 4 which is 0.0001 and now you have 2.0x0.0001 and that equals 0.0002
Answer:
Oxidative phosphorylation
Explanation:
This takes place mostly in the organelle called the mitochondrion.
Oxidation of nutrients in cells by enzymes results in the release of the chemical energy present in the molecular energy.
The NADH and succinate products of the citric acid cycle are also oxidized. All this series of reactions takes place in the Electron transport system.The energy from the oxidation is used to produce adenosine triphosphate (ATP) hence the name oxidative phosphorylation.
The seasons on earth are created by all of the following except:
c. mountain winds
<span>After collison they stick together and have same velocity Vf
From the momentum conservation,
(m1 + m2)Vf = m1v1 + m2v2
Second is moving with half of first cart speed, (m1 + m2)Vf = m1v + m2v / 2
2(m1 + m2)Vf = (2m1v + m2v) =>Vf = ((2m1 + m2) v) / 2(m1 + m2)
Identical carts so m1 = m2 = m
vf = 3mv / 4m => Vf = 3v / 4</span>