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Over [174]
3 years ago
13

Help Please!!!! f(x)=-7x+3, D={-12,-4,3,20}

Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0
Algebra i am really bad at this so don't take my word for it i think maybe 20 SORRY IF WRONG
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Answer:

8,000!

Step-by-step explanation:

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Use the formula slope= y-y/x-x
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A publisher reports that 75% of their readers own a particular make of car. A marketing executive wants to test the claim that t
Korolek [52]

Answer:

The p-value of the test is of 0.0536 > 0.02, which means that there is not sufficient evidence at the 0.02 level to support the executive's claim.

Step-by-step explanation:

A publisher reports that 75% of their readers own a particular make of car. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage.

At the null hypothesis, we test if the proportion is of 75%, that is:

H_0: p = 0.75

At the alternate hypothesis, we test if the proportion is different of 75%, that is:

H_1: p \neq 0.75

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

75% is tested at the null hypothesis:

This means that \mu = 0.75, \sigma = \sqrt{0.75*0.25}

A random sample of 280 found that 70% of the readers owned a particular make of car.

This means that n = 280, X = 0.7

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.7 - 0.75}{\frac{\sqrt{0.75*0.25}}{\sqrt{280}}}

z = -1.93

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion differing from 0.75 by at least |0.7 - 0.75| = 0.05, which is P(|z| > 1.93), which is 2 multiplied by the p-value of z = -1.93.

Looking at the z-table, z = -1.93 has a p-value of 0.0268.

2*0.0268 = 0.0536.

The p-value of the test is of 0.0536 > 0.02, which means that there is not sufficient evidence at the 0.02 level to support the executive's claim.

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3 years ago
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