Answer:
x = 6 cos t
y = 6 sin t
where t varies from 0 to 2pi
Step-by-step explanation:
Given that an ellipse is centred at the origin in xy plane.
So equation would be of the form
Major axis =2a= 12
so a=6
Minor diameter = 8
b = 8/2 = 4
a=6 and b =4
Also (6,0) should correspond to t=0
So best parametrization would be
x = 6 cos t
y = 6 sin t
where t varies from 0 to 2pi
X=1
if you try and find the gradient which is change in y/ change in x so 7/0 you get 0 (no gradient). And it can’t be y= 1 as the y values are 4 and -3
The graph of h(x) = 3x^2 is a curved "bowl" like shape that opens upward. The curve is called a parabola. The two ends go on forever upward. It has symmetry along the y axis.
In contrast, the graph f(x) = x is a straight line that goes through (0,0) and (1,1). This is known as a linear equation.
This is the concept of algebra, to solve the expression we proceed as follows;
cos 2x-cosx=0
cos 2x=cosx
but:
cos 2x+1=2(cos^2x)
thereore;
from:
cos 2x=cos x
adding 1 on both sides we get:
cos 2x+1=cos x+1
2(cos^2x)=cosx+1
suppose;
cos x=a
thus;
2a^2=a+1
a^2-1/2a-1/2=0
solving the above quadratic we get:
a=-0.5 and a=1
when a=-0.5
cosx=-0.5
x=120=2/3π
when x=1
cos x=1
x=0
the answer is:
x=0 or x=2/3π
Answer:
1/15
Step-by-step explanation:
1/5+3+2 all of the marbles
2/10 odds of drawing an orange marble(bc 2 orange marble)
3/9 because to get 3 green and 1 marble is removed and 9 is total marbles left
2/10*3/9=1/15 muliply odds because 2 draws of marbles