Answer:
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Answer: The average rate of the reaction during this time interval is, 0.005 M/s
Explanation:
The given chemical reaction is:
The expression will be:
where,
= final concentration of 
= 0.025 M
= initial concentration of = 0.100 M
= final time = 15 minutes
= initial time = 0 minutes
Putting values in above equation, we get:
Hence, the average rate of the reaction during this time interval is, 0.005 M/s
Answer: 20 mg Te-99 remains after 12 hours.
Explanation: N(t) = N(0)*(1/2)^(t/t1/2)
N(t) = (80 mg)*(0.5)^(12/6)
N(t) = 20 mg remains after 12 hours
Answer:
6.3moles
Explanation:
The balanced chemical equation for the decomposition of phosphorus oxychloride (POCl3) is as follows:
POCl3 → POCl + Cl2
Based on the above decomposition reaction, it shows that;
1 mol of POCl3 will decompose to give 1 mole of Cl2
Hence, 6.3 moles of POCI3 will give 6.3 moles of Cl2.
