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pishuonlain [190]
3 years ago
14

Is conductivity a chemical or physical property​

Chemistry
1 answer:
MatroZZZ [7]3 years ago
8 0
Answer:

It is a physical property




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11. Determine the empirical formula of a compound containing 3.6 g of carbon, 0.9 g of
Norma-Jean [14]

Answer:

The empirical formula is C2H6O

Explanation:

Please see attachment for explanation on how to solve for the empirical formula.

7 0
3 years ago
Volume is the independent or dependent variable
m_a_m_a [10]

Answer:

Independent

Explanation:

Independent Variable is the volume of the object. Dependent Variable is the mass of the object. So it

7 0
3 years ago
Given the reaction for the corrosion of aluminum: 4 Al + 3 O2 --> 2 Al2O3, which half-reaction correctly represents the oxida
Pavel [41]

Answer:

Option B, Al --> Al3+ + 3e-

Explanation:

Oxidation is defined as the process of losing electron by a molecule, atom or anion  thereby acquiring oxidation state i.e the positive charge. Reduction on the other hand is the process in which an atom, ion or molecule gains electron and gains negative charge on it.  

For example – In the reaction, H2 + F2 → 2 HF, hydrogen is oxidized H2 → 2 H+ + 2 e-  as it looses electron while fluorine is being reduced F2 + 2 e- → 2 F-

This is happening in the option B

5 0
3 years ago
What is the empirical formula of a compound which contains 84.4% c and 15.6% h by mass?
podryga [215]

Answer: The empirical formula for the given compound is CH_2

Explanation : Given,

Percentage of C = 84.4 %

Percentage of H = 15.6 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 84.4 g

Mass of H = 15.6 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{84.4g}{12g/mole}=7.03moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{15.6g}{1g/mole}=15.6moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 7.03 moles.

For Carbon = \frac{7.03}{7.03}=1

For Hydrogen  = \frac{15.6}{7.03}=2.22\approx 2

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 2

Hence, the empirical formula for the given compound is C_1H_2=CH_2

7 0
3 years ago
Enter the chemical equation for the formation of Ca(NO3)2(s) from its respective elements in their standard states.
Afina-wow [57]

Answer:

Ca(s)  +  N₂(g)  +  3O₂(g) →  Ca(NO₃)₂ (s)

Explanation:

The reaction of the formation of Ca(NO₃)₂(s) , is as follows -

Ca  +  N₂  +  O₂ →  Ca(NO₃)₂

The above reaction , can be balanced by adding whole numbers ,

Hence , the balanced reaction is as follows -

Ca  +  N₂  +  3O₂ →  Ca(NO₃)₂

The states of the respective molecules is -

the state at which the atoms are most stable or the state at which the atoms are most commonly found .

Hence ,

Calcium is most stable in solid state

Oxygen  is most stable in gaseous state

Nitrogen  is most stable in gaseous state

hence , the balanced reaction with all the states mentioned is as follows -

Ca(s)  +  N₂(g)  +  3O₂(g) →  Ca(NO₃)₂ (s) .

5 0
3 years ago
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