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rjkz [21]
3 years ago
15

How does amount of greenhouse gases affect the temperature of the Earth's atmosphere?

Chemistry
2 answers:
Helen [10]3 years ago
8 0

greenhouse gases can cause Earth's atmosphere to trap more and more heat. This causes Earth to warm up.

klio [65]3 years ago
4 0
It causes it to trap up more heat
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Canivorous plants is the correct answer for your question
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Bobby found that water has a high boiling point and concluded this was because water intermolecular forces. Based on the data, i
Art [367]

Yes, Bobby is correct

Explanation:

Anomalously high boiling point of water is as a result of the intermolecular forces between the molecules of water.

The intermolecular forces found in water are the very strong hydrogen bonds.  The bulk of the physical properties of matter are due to the intermolecular forces that they possess.

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5 0
4 years ago
rate of a certain reaction is given by the following rate law: rate Use this information to answer the questions below. What is
Sunny_sXe [5.5K]

Complete Question

The  rate of a certain reaction is given by the following rate law:

            rate =  k [H_2][I_2]

rate Use this information to answer the questions below.

What is the reaction order in H_2?

What is the reaction order in I_2?

What is overall reaction order?

At a certain concentration of H2 and I2, the initial rate of reaction is 2.0 x 104 M / s. What would the initial rate of the reaction be if the concentration of H2 were doubled? Round your answer to significant digits. The rate of the reaction is measured to be 52.0 M / s when [H2] = 1.8 M and [I2] = 0.82 M. Calculate the value of the rate constant. Round your answer to significant digits.

Answer:

The reaction order in H_2 is  n =  1

The reaction order in I_2 is  m = 1

The  overall reaction order z =  2

When the hydrogen is double the the initial rate is   rate_n  =  4.0*10^{-4} M/s

The rate constant is   k = 35.23 \  M^{-1} s^{-1}

Explanation:

From the question we are told that

   The rate law is  rate =  k [H_2][I_2]

   The rate of reaction is rate =  2.0 *10^{4} M /s

Let the reaction order for H_2 be  n and for I_2  be  m

From the given rate law the concentration of H_2 is raised to the power of 1 and this is same with I_2 so their reaction order is  n=m=1

   The overall reaction order is  

               z  = n +m

               z  =1 +1

               z  =2

At  rate =  2.0 *10^{4} M /s

        2.0*10^{4}  = k  [H_2] [I_2] ---(1)

= >    k  = \frac{2.0*10^{4}}{[H_2] [I_2]  }

given that the concentration of hydrogen is doubled we have that

            rate  = k [2H_2] [I_2] ----(2)

=>      k = \frac{rate_n  }{ [2H_2] [I_2]}

 So equating the two k

           \frac{2.0*10^{4}}{[H_2] [I_2]  } = \frac{rate_n  }{ [2H_2] [I_2]}

    =>    rate_n  =  4.0*10^{-4} M/s

So when

      rate_x =  52.0 M/s

        [H_2] = 1.8 M

         [I_2] =  0.82 \ M

We have

      52 .0 =  k(1.8)* (0.82)

     k = \frac{52 .0}{(1.8)* (0.82)}

      k = 35.23 M^{-2} s^{-1}

     

     

3 0
3 years ago
Does the equation describe a chemical change or a physical change? Explain your reasoning.
Neporo4naja [7]

Answer:

Chemical change

Explanation:

There are types of changes in nature namely: physical change and chemical change. A physical change is a change that does not alter the chemical composition of the substances involved, hence, no new substances are formed. On the other hand, a chemical change changes the chemical composition of the involved substances to form new substances.

Based on the definition of the types of changes below, the equation depicted in this question is a CHEMICAL CHANGE because it involves a rearrangement of the atoms of each element in the reactants to produce new sets of products with a new chemical formula.

C17H17ON3(s) + 2C4H6O3(l) → C21H21O5N(s) + 2C2H4O2(l)

7 0
3 years ago
In the combustion of gasoline, if it is calculated that 250.15 g of CO2 will be produced, but only 212.48 g are collected, what
S_A_V [24]

Answer:

To calculate the Carbon Dioxide - CO 2 - emission from a fuel, the carbon content of the fuel must be multiplied with the ratio of molecular weight of CO 2 (44) to the molecular weight of Carbon (12) -> 44 / 12 = 3.7 Emission of CO 2 from combustion of some common fuels are indicated in the table

Explanation:

8 0
3 years ago
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