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kupik [55]
2 years ago
10

To 225 mL of a 0. 80 M solution of Kl, a student adds enough water to make 1. 0 L of a more dilute Kl solution. What is the mola

rity of the new solution?
Chemistry
1 answer:
Lady_Fox [76]2 years ago
7 0

Answer: 0.18 M

Explanation:

Initial molarity, M1 = 0.8 M

Initial olume, V1 = 225 ml

Final volume, V2 = 1000 ml

Final Molarity, M2 = M1V1/V2

= 0.8 x 225/1000

= 0.18 M

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Consider a situation in which 211 g
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Answer:

3.00 mol

Explanation:

Given data:

Mass of P₄ = 211 g

Mass of oxygen = 240 g

Moles of P₂O₅ = ?

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Chemical equation:

P₄ + 5O₂       →     2P₂O₅

Number of moles of P₄:

Number of moles = mass/ molar mass

Number of moles = 211 g / 123.88 g/mol

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Number of moles of O₂ :

Number of moles = mass/ molar mass

Number of moles = 240 g / 32g/mol

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Now we will compare the moles of product with reactant.

                       O₂         :         P₂O₅

                        5          :           2

                        7.5       :        2/5×7.5 = 3.00

                       P₄          :         P₂O₅

                        1           :           2

                       1.7         :       2×1.7 = 3.4 mol

Oxygen is limiting reactant so the number of moles of P₂O₅ are 3.00 mol.

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Mass = number of moles × molar mass

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