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3 years ago

3g of magnesium reacted w 0.2 moles of ethanoic acid. Calculate the number of moles of magnesium used

Chemistry

1 answer:

marishachu [46]3 years ago

4 0

Answer:

0.1 moles of magnesium

Explanation:

Mg(s) + 2CH3COOH(aq) -------> Mg(CH3COO)2(aq) + H2(g)

Since the reaction is 1:2 in mole ratio,

1 mole of magnesium reacts with 2 moles of ethanoic acid

x moles of magnesium will react with 0.2 moles of ethanoic acid

2x = 0.2

x = 0.2/2 = 0.1 moles of magnesium used

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A 254.5 g sample of a white solid is known to be a mixture of KNO3, BaCl2, and NaCl. When 116.5 g of this mixture is dissolved i

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Answer:

Mass of KNO3 in the original mix is 146.954 g

Explanation:

mass of $KNO_3$ in original 254.5 mixture.

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note that, the Cl- derive from both, $BACl_2 and NaCl$

mole of Cl- f NaCl $= (1.3891) - (0.2926\times 2) = 0.8039$ mol of Cl-

mol of NaCl = 0.8039 moles

$mass = mol\times Molecular\ Weight = 0.8039 \times 58 = 46.626\ g \ of \ NaCl$

then

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Answer:

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