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inysia [295]
3 years ago
9

Write a word phrase for the expression 3(w-1) then simplify

Mathematics
1 answer:
enot [183]3 years ago
6 0
The word phrase would be that any number w less than 1 is multiplied by 3. To simplify it, you can distribute 3 to the terms inside the parentheses. It is simplified as follows:

3(w - 1)
3w - 3

Hope this answers the question. Have a nice day.
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There are three monomials such that the greatest common factor of the first and second monomial is 2xy and the greatest common f
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3 years ago
What is the sum of 2x^2 and 2x^3
jeyben [28]

For this case we have the following expression:

2x ^ 2 + 2x ^ 3

The terms are not similar, so they cannot be added.

<em>Examples of similar terms:</em>

x ^ 3 + x ^ 3 = 2x ^ 3\\3x ^ 4 + 2x ^ 4 = 5x ^ 4

Then, the expression given can only be rewritten as:

2 (x ^ 2 + x ^ 3)

This is taking common factor 2 to both terms.

Answer:

2 (x ^ 2 + x ^ 3)

7 0
3 years ago
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 65 inches and standard deviation 4 inch
Serhud [2]

Answer:

Step-by-step explanation:

<u>a)</u>

  • Given that ; X ~ N ( µ = 65 , σ = 4 )
  • P ( 64 < X < 66 )

From application of normal distribution ;

  • Z = ( X - µ ) / σ, Z = ( 64 - 65 ) / 4,  Z = -0.25
  • Z = ( 66 - 65 ) / 4,  Z = 0.25

Hence, P ( -0.25 < Z < 0.25 ) = P ( 64 < X < 66 ) = P ( Z < 0.25 ) - P ( Z < -0.25 ) P ( 64 < X < 66 ) = 0.5987 - 0.4013

  • P ( 64 < X < 66 ) = 0.1974

b) X ~ N ( µ = 65 , σ = 4 )

  • P ( 64 < X < 66 )

From normal distribution application ;

  • Z = ( X - µ ) / ( σ / √(n)), plugging in the values,
  • Z = ( 64 - 65 ) / ( 4 / √(12)) = Z = -0.866
  • Z = ( 66 - 65 ) / ( 4 / √(12)) = Z = 0.866

P ( -0.87 < Z < 0.87 )

  • P ( 64 < X < 66 ) = P ( Z < 0.87 ) - P ( Z < -0.87 )
  • P ( 64 < X < 66 ) = 0.8068 - 0.1932
  • P ( 64 < X < 66 ) = 0.6135

c) From the values gotten for (a) and (b), it is indicative that the probability in part (b) is much higher because the standard deviation is smaller for the x distribution.

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