Question

For the given current of 300 A and time interval 0.250 s, how many conduction electrons are transferred?

Answer 1

Answer : The number of electrons transferred are, $4.68\times 10^{20}$

Explanation :

First we have to calculate the charge on electron.

Formula used :

$Q=I\times t$

where,

Q = charge on electron = ?

I = current = 300 A

t = time = 0.250 s

Now put all the given values in the above formula, we get:

$Q=300A\times 0.250s$

$Q=75C$

Now we have to calculate the number of electrons are transferred.

Formula used :

$Q=ne\\\\n=\frac{Q}{e}$

where,

n = number of electrons transferred = ?

Q = charge on electrons = 75 C

e = charge on 1 electron = $1.602\times 10^{-19}C$

Now put all the given values in the above formula, we get:

$n=\frac{75C}{1.602\times 10^{-19}C}$

$n=4.68\times 10^{20}$

Thus, the number of electrons transferred are, $4.68\times 10^{20}$